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Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{1}^{2} \left X \right dx\]
 one year ago

Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
I got 3/2 this is the wrong answer the correct answer is 2.5
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Can you show me your working ?
 one year ago

Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
\[\left x \right \] \[\frac{ x^2 }{ 2 }\] \[(\frac{ 2^2 }{ 2 }) (\frac{ 1^2 }{ 2 })\] (4/2)(1/2) 3/2
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
1) Convention suggests that \(X\) is NOT the same as \(x\). Please don't switch variable in the middle of a problem. 2) You have simply ignored the absolute value. That's no good. Split the integral at \(x = 0\) and see if you can manage a different result.
 one year ago

Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
I'm still not sure what to do
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1358608829929:dw
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
\(\int\limits_{1}^{2}x\;dx = \int\limits_{1}^{0}x\;dx + \int\limits_{0}^{2}x\;dx = \int\limits_{1}^{0}(x)\;dx + \int\limits_{0}^{2}(x)\;dx\)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
That should help
 one year ago

Brooke_army Group TitleBest ResponseYou've already chosen the best response.0
thanks I will try that
 one year ago
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