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omgitsana

  • 3 years ago

find the integral

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  1. omgitsana
    • 3 years ago
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    |dw:1358617791231:dw|

  2. omgitsana
    • 3 years ago
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    i attempted to solve it but i can't get the answer.. which is 24

  3. Jonask
    • 3 years ago
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    \[\frac{1}{3}\ln(x^3+3x)\]

  4. Jonask
    • 3 years ago
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    just guessed

  5. omgitsana
    • 3 years ago
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    yeah i got up to there but i can't get the answer :/

  6. rishabh.mission
    • 3 years ago
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    1st take x2=t nd find is dx/dy

  7. rishabh.mission
    • 3 years ago
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    its easy but i dont have pen/pencil let me try give few min.

  8. Jonask
    • 3 years ago
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    \[\huge{\ln(x^2+3x)}\huge{|_{1}^{3}}={\ln(3^2+3(3))-\ln(1^2+3(1))}\]

  9. Jonask
    • 3 years ago
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    sorry i forgot\[\frac{1}{3}\] on boh sides

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