zeig_101
  • zeig_101
*reward: 1 medal for answers* 1) If the current in a wire is at 0.5 A and the voltage is measured at 100 volts, what is the resistance in the wire? 2)What is the electric power used by an appliance if the current is 2 A and the voltage is 50 volts? 3)How are sound waves produced, and what impacts do different types of matter have on the speed of the wave? 4)What is the electromagnetic spectrum? Explain and give an example. 5)http://img254.imageshack.us/img254/6528/459431120201182932am187.png In the figure shown, how could you determine the wavelength? 6)Explain how you can quickly determine whether a string of lights is wired in series or in parallel.
Physics
chestercat
  • chestercat
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inkyvoyd
  • inkyvoyd
Ohm's law: I=V/R
zeig_101
  • zeig_101
See, I dont know how to use Ohm's law
inkyvoyd
  • inkyvoyd
For number one, I=0.5 and V=100

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inkyvoyd
  • inkyvoyd
so you just back substitute the numbers in: (0.5)=100/R Next you isolate R. 0.5R=100 R=200
zeig_101
  • zeig_101
ok, so, .5 A=100V/X?
inkyvoyd
  • inkyvoyd
yup
zeig_101
  • zeig_101
so, 50a=x?
inkyvoyd
  • inkyvoyd
no. A is a unit.
inkyvoyd
  • inkyvoyd
It's not a variable. If it helps you, use Amps instead of A
zeig_101
  • zeig_101
Ok, I don't get this can you walk me through it?
inkyvoyd
  • inkyvoyd
Okay. We know that I=V/R. We also know that I=0.5Amps and V=100Volts Do you follow?
zeig_101
  • zeig_101
What do the things in I=V/r mean?
inkyvoyd
  • inkyvoyd
It's a relationship between current, voltage, and resistance. I is a variable that represents current. V is a variable that represents voltage. R is a variable that represents resistance. We usually give these measurements in Amperes (A), Volts (V) and Ohms (omega), respectively.
zeig_101
  • zeig_101
ok, so its really C=V/R?
inkyvoyd
  • inkyvoyd
We don't use C for current. We use I. This is out of habit, so use I okay?
zeig_101
  • zeig_101
ok
inkyvoyd
  • inkyvoyd
(In mathematics we often encounter constants and we represent them with C's. If we used C for current it would be confused with other values and would not be clear). BUt essentially yes, the relationship is I=V/R
zeig_101
  • zeig_101
ok
zeig_101
  • zeig_101
so 0.5=100/R
inkyvoyd
  • inkyvoyd
yes.
zeig_101
  • zeig_101
now where do i go from there?
inkyvoyd
  • inkyvoyd
Multiply both sides by R.
zeig_101
  • zeig_101
so,0.5R=100?
inkyvoyd
  • inkyvoyd
Yup.
zeig_101
  • zeig_101
ok, so divide by .5?
zeig_101
  • zeig_101
R=100/0.5 R=200
inkyvoyd
  • inkyvoyd
Yes.
inkyvoyd
  • inkyvoyd
Can you do number 2?
zeig_101
  • zeig_101
What is the electric power used by an appliance if the current is 2 A and the voltage is 50 volts? I=V/r 2=50/r 2r=50 r=100?
inkyvoyd
  • inkyvoyd
btw, the units for the resistance are in ohms.
inkyvoyd
  • inkyvoyd
no, power is P=IV x.x
inkyvoyd
  • inkyvoyd
sorry they are different formulas.
zeig_101
  • zeig_101
What is the electric power used by an appliance if the current is 2 A and the voltage is 50 volts? P=I*V? P=2A*50V P=100?
inkyvoyd
  • inkyvoyd
100 watts
zeig_101
  • zeig_101
ok
inkyvoyd
  • inkyvoyd
Do you need help with the rest?

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