anonymous
  • anonymous
Help please?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
I have attached it
anonymous
  • anonymous
take the frequency for that interval and divide it by the total frequency

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anonymous
  • anonymous
I got 0.2237
anonymous
  • anonymous
and it should be skewed to right
anonymous
  • anonymous
32/143 is approximately 0.2238 when rounded to four decimals, yep and yes it looks like the frequencies are slightly shifted to the right
anonymous
  • anonymous
what about the mean and meadian ?

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