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 2 years ago
find a quadratic function in standard for that has the following points: (1,2); (2,2); (3,4).
 2 years ago
find a quadratic function in standard for that has the following points: (1,2); (2,2); (3,4).

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dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1plug each point into equation: \[y = ax^{2} +bx +c\] this will give 3 equations with 3 variables (a,b,c) solve system of 3 equations with matrices or elimination

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0how do i place them in that equation without an a b and c ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1for (1,2) ..... x=1 and y=2 ==> 2 = a*(1)^2 + b*1 + c > 2 = a+b+c

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0if i plug it in wouldnt a still be squared or somethin ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1a is not squared ... the "x" is squared

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0oh. okay so after i do that do i add all of them together ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1well you need to know how to solve a system of 3 equations

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0what do you mean ?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1after plugging in the points, you get a + b +c = 2 4a +2b +c = 2 9a + 3b +c = 4 you need to solve for a,b,c

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0im trying to write down and figure which numbers can work for all three

Beautiful_Lier96
 2 years ago
Best ResponseYou've already chosen the best response.0omg thank you. i was going to be thinking forever. and im extra tired. i know i shoulda did it by myself but idk. may you help me with one more question: The weight of a tennis ball must be 57.7 grams, plus or minus 1.7 grams. write an absolute value inequality to illustrate this rule...

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1"Oh my god, thank you. I would have been thinking about this for a long time, and I'm extra tired today. I know that I should have solved it on my own. Can you help me with another problem..." 57.7x<1.7
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