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What equations have you set up to model this problem?

hola

I'd first start by deciphering everything you have

first lets make 2010 your P-not or
\[P_0=P(0)\]

so at
\[P(0)=50,000\]

for checkerville yes

that is \[50000(1.07)^x=70000(.96)^x\]

essentially the same thing lol

at any rate, solve via \[x=\frac{\ln(1.4)}{\ln(\frac{1.07}{.96})}\]

say this exact same problem yesterday. they really reach for these word problems, don't they?

satellite, your equation is correct and your final solution is also correct

nah it's because i meant to put the rate as 1.07 and .96 so you'd get the same thing