Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

fruitbat

  • 2 years ago

asdfghjkl

  • This Question is Closed
  1. binarymimic
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What equations have you set up to model this problem?

  2. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hola

  3. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'd first start by deciphering everything you have

  4. binarymimic
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If you are unsure where to begin, review exponential functions ( http://www.regentsprep.org/Regents/math/ALGEBRA/AE7/ExpDecayL.htm) You should obtain \[50000(1 + 0.07)^{x} = 70000(1 - 0.04)^{x}\]

  5. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    first lets make 2010 your P-not or \[P_0=P(0)\]

  6. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so at \[P(0)=50,000\]

  7. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for checkerville yes

  8. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lets rephrase what your equation is \[P=ce^{kt}\] where p is your population , c is a constant unknown atm and k is your rate. t is time. if we put in P(0) you get \[50,000=ce^{0}=c\] \[P=50,000e^{kt}\] since we know the rate at which it increases 7% \[P=50,000e^{.07t}\] next doing for checker ville you get \[P=70,000e^{-.04t}\]

  9. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    At P1=P2 is when one will exceed the other and the other will be below soooo \[70,000e^{-.04t}=50,000e^{.07t}\] solve for t

  10. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i am going to make a guess that you are supposed to use \[50000(1 + 0.07)^{x} = 70000(1 - 0.04)^{x}\]

  11. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that is \[50000(1.07)^x=70000(.96)^x\]

  12. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    essentially the same thing lol

  13. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    divide by 50000 get \[ 91.07)^x=1.4(.96)^x\]divide by\[ (.96)^x\] get \[\left(\frac{1.07}{.96}\right)^x=1.4\]

  14. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @Outkast3r09 yeah it is the same except that i am thinking that because it say 7% per year it is using \((1.07)^x\) rather than \(e^{.07x}\) but i could be wrong

  15. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    at any rate, solve via \[x=\frac{\ln(1.4)}{\ln(\frac{1.07}{.96})}\]

  16. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    say this exact same problem yesterday. they really reach for these word problems, don't they?

  17. binarymimic
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    satellite, your equation is correct and your final solution is also correct

  18. Outkast3r09
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nah it's because i meant to put the rate as 1.07 and .96 so you'd get the same thing

  19. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.