anonymous
  • anonymous
Linear algebra question?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Anyone want to help me get started? I am pretty sure I can do the rest on my own.
anonymous
  • anonymous
Represent the system in matrix form

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yep, that's what I did.
anonymous
  • anonymous
@Cecily
anonymous
  • anonymous
How do I go on from there?
anonymous
  • anonymous
@zepdrix @Outkast3r09
anonymous
  • anonymous
@dumbcow
sirm3d
  • sirm3d
take the determinant of the coefficient matrix, and set it equal to zero.
anonymous
  • anonymous
Woah woah!!! We haven't learned what a determinant is yet. :P .
sirm3d
  • sirm3d
okay. how about gauss-jordan reduction?
anonymous
  • anonymous
Yeah. We learned that.
sirm3d
  • sirm3d
i got something easier than gauss-jordan. multiply equation 2 by (-1), and equation 3 by 2, then add the two equations.
anonymous
  • anonymous
Elimination?
sirm3d
  • sirm3d
yup.
anonymous
  • anonymous
3y-3z=-a+2 ?
sirm3d
  • sirm3d
not 3y+3z = -a + 2 ?
anonymous
  • anonymous
Yeah. My mistake.
anonymous
  • anonymous
Allright, what next?
sirm3d
  • sirm3d
use that equation with equation 1 to eliminate both y and z.
anonymous
  • anonymous
1 sec.
anonymous
  • anonymous
THat dosen't eliminate it. It makes it bigger.
sirm3d
  • sirm3d
bx + 3y + 3z = a 3y + 3z = 2 - a subtract.
anonymous
  • anonymous
I used substitution instead. Should till be valid right?
sirm3d
  • sirm3d
or if you wish to substitute...
sirm3d
  • sirm3d
that's valid too.
sirm3d
  • sirm3d
bx + (2-a) =a bx = 2a - 2
anonymous
  • anonymous
|dw:1358650895030:dw|
sirm3d
  • sirm3d
you're not to eliminate a, but y and z.
anonymous
  • anonymous
Right.
anonymous
  • anonymous
Lets us elimination then lol.
anonymous
  • anonymous
bx=2a-2?
sirm3d
  • sirm3d
yup.
anonymous
  • anonymous
Now would I solve for a and substitute this into equation 2?
sirm3d
  • sirm3d
now if you put b = 1, and a any real number other than 1, say 3, 0x = 4 0 = 4 which is clearly false.
sirm3d
  • sirm3d
err. i mean put b = 0.
anonymous
  • anonymous
Why can I put 1?
anonymous
  • anonymous
for a*
anonymous
  • anonymous
Ohh never mind. I see why.
anonymous
  • anonymous
For infinitely many solutions I would make 0=0 right?
sirm3d
  • sirm3d
right about that.
anonymous
  • anonymous
Okay what about a unique solution? @sirm3d
sirm3d
  • sirm3d
unique solution when b is not equal to zero.
anonymous
  • anonymous
and a is 1 right?
sirm3d
  • sirm3d
any value of a for as long as b not zero will yield a unique solution
anonymous
  • anonymous
Thanks so much!
sirm3d
  • sirm3d
yw.

Looking for something else?

Not the answer you are looking for? Search for more explanations.