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Do you know point slope form of the equation of a line?

no

\[y-y _{1}=m(x-x _{1})\]

dont i need two points??

replace ysub1 with 12. replace m with -1. replace xsub1 with -3 and solve for y

ok im a little lost now

wont i still have x?

\[y-12=-1(x- -3)\]

\[y-12=-1(x+3)\]

\[y-12=-x-3\]

y=-x+9

ohhh ok i understand now thanks again..

And that is the equation of a line whose slope is -1 and passes through the point
(-3,12).