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6. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)
95.1s and 108.7s
10.2s and 101.9s
108.7s and 10.2s
95.1s and 10.2s
 one year ago
 one year ago
6. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point) 95.1s and 108.7s 10.2s and 101.9s 108.7s and 10.2s 95.1s and 10.2s
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.1
strange way to ask: "solve \(1.553t=0.1\) for \(t\)
 one year ago

CuriousPerson55555Best ResponseYou've already chosen the best response.0
how do u slove?
 one year ago

binarymimicBest ResponseYou've already chosen the best response.1
1.5−53t = 0.1 implies 1.5  53t = 0.1 and 53t  1.5 = 0.1
 one year ago

binarymimicBest ResponseYou've already chosen the best response.1
you just solve for t in each equation to get each answer. your values of t will be in hours, so you have to convert them into seconds
 one year ago

binarymimicBest ResponseYou've already chosen the best response.1
i'll do the first one for you 1.5  53t = 0.1 1.5 = 0.1 + 53t 1.4 = 53t 0.026415 = t 0.026415 * 60 min/h * 60 s/min = 95.094 seconds or about 95.1 seconds
 one year ago

CuriousPerson55555Best ResponseYou've already chosen the best response.0
now i c wat u do thanks
 one year ago
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