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CuriousPerson55555
 3 years ago
6. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)
95.1s and 108.7s
10.2s and 101.9s
108.7s and 10.2s
95.1s and 10.2s
CuriousPerson55555
 3 years ago
6. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point) 95.1s and 108.7s 10.2s and 101.9s 108.7s and 10.2s 95.1s and 10.2s

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1strange way to ask: "solve \(1.553t=0.1\) for \(t\)

CuriousPerson55555
 3 years ago
Best ResponseYou've already chosen the best response.0how do u slove?

binarymimic
 3 years ago
Best ResponseYou've already chosen the best response.11.5−53t = 0.1 implies 1.5  53t = 0.1 and 53t  1.5 = 0.1

binarymimic
 3 years ago
Best ResponseYou've already chosen the best response.1you just solve for t in each equation to get each answer. your values of t will be in hours, so you have to convert them into seconds

binarymimic
 3 years ago
Best ResponseYou've already chosen the best response.1i'll do the first one for you 1.5  53t = 0.1 1.5 = 0.1 + 53t 1.4 = 53t 0.026415 = t 0.026415 * 60 min/h * 60 s/min = 95.094 seconds or about 95.1 seconds

CuriousPerson55555
 3 years ago
Best ResponseYou've already chosen the best response.0now i c wat u do thanks
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