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6. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = |1.5 – 53t|. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point) 95.1s and 108.7s 10.2s and 101.9s 108.7s and 10.2s 95.1s and 10.2s

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strange way to ask: "solve \(|1.5-53t|=0.1\) for \(t\)
how do u slove?
|1.5−53t| = 0.1 implies 1.5 - 53t = 0.1 and 53t - 1.5 = 0.1

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Other answers:

you just solve for t in each equation to get each answer. your values of t will be in hours, so you have to convert them into seconds
i'll do the first one for you 1.5 - 53t = 0.1 1.5 = 0.1 + 53t 1.4 = 53t 0.026415 = t 0.026415 * 60 min/h * 60 s/min = 95.094 seconds or about 95.1 seconds
now i c wat u do thanks

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