A committee of 5 people is chosen from 6 men and 4 women. in how many ways can this be done 1) if there must be more men than women on the commitee. 2) if there must be 3 men and 2 women, and one particular woman refuses to be on the commitee with one particular man

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A committee of 5 people is chosen from 6 men and 4 women. in how many ways can this be done 1) if there must be more men than women on the commitee. 2) if there must be 3 men and 2 women, and one particular woman refuses to be on the commitee with one particular man

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Permutations and combinations....
More men is when No. of men is 3 or No. of men is 4 or No. of men is 5
Which means there must be atleast three men

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Other answers:

6C3*7C2 First we choose at least three 3 men then choose any two people from the remaining people
got it?
the answer is 186
the marking scheme says choose 4 men and 1 women or 5 men and no women. i don't understand why we can't choose 3 men and 2 women.
u can do it too
I mean u can choose 3 men and 2 women
yeah but i wonder why in my mark scheme it's not given. that's why the total answer is 186 but i got 180. by choosing 4 men, 1 women and 3 men 2 women. thanks anyways..:)
do you know how to do the second part?
6C3 * 4C2 + 6C4 *4C1 +6C5 =120+60+6=186
U forgot the case when all are men
Can someone tell me why 6C3 *7C2 doest work
I was also wondering the same thing. hmm..
M1 M2 M3 M4 M5 M6 W1 W2 W3 W4 Can we try to rationalize ?
@sauravshakya, can you explain how u got 6C3*7C2 ?
First we choose at least three 3 men then choose any two people from the remaining people

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