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I know that log base 25 is actually 1/2 log base 5 y

sure, first you need to know this property of log,
\[\log_ba= \dfrac{\log a}{\log b}\]

understood the property

so, \(\log_5 y= ...?? \\ \log_{25}y=... ?\)

log base 5 y = log y / log 5 and log base 25 y = log y/ log 25

good :)
now \(\log x^n=n \log x \\ so, \log 25=.... ?\)

2 log 5 sir

so, now you can put log y =x
and the equation will become ...?

i dont know

can you give me the full step solution lol

i am getting confuse here

\(3x/log 5 -x/(2log 5) = 10 \\ \)
got this step first ?

where x=log y

keep it going

multiply both sides by 2log 5
6x - x = 20 log 5
5x = 20 log 5
got this much ?

The first step that you posted is that the first step of showing the workings?

if you understand how to solve, you will be able to show the workings on your own....

20 log 5 means 20 log base 5?

i dont get it

i think that is where the problem lies in. if not, i could easily understand your workings.

yes

okay so there is only 1 value for x?

yes, and so 1 value of y.

so what is it?

i want to see whether i got the right answer.