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Sgstudent
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3 log base 5 y  1og base 25 y = 10
This is a difficult question for me to solve and i hope you would help me thanks.
 one year ago
 one year ago
Sgstudent Group Title
3 log base 5 y  1og base 25 y = 10 This is a difficult question for me to solve and i hope you would help me thanks.
 one year ago
 one year ago

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Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
I know that log base 25 is actually 1/2 log base 5 y
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
sure, first you need to know this property of log, \[\log_ba= \dfrac{\log a}{\log b}\]
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
understood the property
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, \(\log_5 y= ...?? \\ \log_{25}y=... ?\)
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
log base 5 y = log y / log 5 and log base 25 y = log y/ log 25
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
good :) now \(\log x^n=n \log x \\ so, \log 25=.... ?\)
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
2 log 5 sir
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, now you can put log y =x and the equation will become ...?
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i dont know
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
can you give me the full step solution lol
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i am getting confuse here
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(3x/log 5 x/(2log 5) = 10 \\ \) got this step first ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
where x=log y
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
keep it going
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
multiply both sides by 2log 5 6x  x = 20 log 5 5x = 20 log 5 got this much ?
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
The first step that you posted is that the first step of showing the workings?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if you understand how to solve, you will be able to show the workings on your own....
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
20 log 5 means 20 log base 5?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i have made the base unspecified (when its unspecified, by default its 10), so 20 log 5 means 20 times log of 5 (with the base 10)
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i dont get it
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i think that is where the problem lies in. if not, i could easily understand your workings.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\log_ba= \dfrac{\log_{10} a}{\log_{10} b} \\\log _{25}y =\dfrac{\log_{10} y}{\log_{10} 25} \) now ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\log_ba= \dfrac{\log_{10} a}{\log_{10} b} \\\log _{25}y =\dfrac{\log_{10} y}{\log_{10} 25}=\dfrac{\log_{10} y}{2\log_{10} 5}\\\log_{5}y=\dfrac{\log_{10} y}{\log_{10} 5} \\ let \log y=x \\ 3x/\log 5 x/(2\log 5)=10 \implies 6xx=20\log_{10}5\\x=4\log_{10}5 \\ \log_{10} y = \log _{10}5^4 \implies y= 5^4\)
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
okay so there is only 1 value for x?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, and so 1 value of y.
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
so what is it?
 one year ago

Sgstudent Group TitleBest ResponseYou've already chosen the best response.0
i want to see whether i got the right answer.
 one year ago
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