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msingh

  • 3 years ago

Can anyone derive me the formula for the nth term from the Last , of A.P?

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  1. ash2326
    • 3 years ago
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    You want to derive the formula for the nth term of an A.P?

  2. msingh
    • 3 years ago
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    kk..

  3. ash2326
    • 3 years ago
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    Let the first term be a1 and the common difference be d now second term will be a2=a1+d third term will be a3=a1+d+d=a1+2d Do you get this part?

  4. msingh
    • 3 years ago
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    yes..

  5. ash2326
    • 3 years ago
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    Now if we go on like that, 4th term is \[a_4=a_1+3d\] Hence nth term will be \[a_n=a_1+(n-1)d\] Do you understand this?

  6. msingh
    • 3 years ago
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    yes..and thank u

  7. msingh
    • 3 years ago
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    one question..why do we add 1 on last step

  8. msingh
    • 3 years ago
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    because thee are n terms and before we have n-1 terms

  9. msingh
    • 3 years ago
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    it goes on decreasing such as n, n-1, n-2...

  10. ash2326
    • 3 years ago
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    I don't get you, where do you have doubt?

  11. msingh
    • 3 years ago
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    an=a1+(n−1)d, y there is 1

  12. ash2326
    • 3 years ago
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    you mean the 1 in n-1?

  13. msingh
    • 3 years ago
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    yes.

  14. ash2326
    • 3 years ago
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    for seond term a2, we have d or 1d for third term a3, we have 2 d In the formula we have d times ( one no. less than the term no. ) That's why for n we have 1 less than n i.e n-1

  15. msingh
    • 3 years ago
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    kkk

  16. ash2326
    • 3 years ago
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    Do you understand?

  17. msingh
    • 3 years ago
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    yes

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