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rizwan_uet Group TitleBest ResponseYou've already chosen the best response.2
dw:1358703755414:dw
 one year ago

texaschic101 Group TitleBest ResponseYou've already chosen the best response.0
does this help ?.... http://www.purplemath.com/modules/quadform.htm
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.0
\[ax ^{2}+bx+c=0\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.0
is called quadratic equation
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.0
the solution of this quadratic equation is \[x=\frac{ b \pm \sqrt{b ^{2}4ca} }{ 2a }\]
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ b \pm \sqrt{b^24ac} }{ 2a }\] where you have a polynomial in the form \[ax^2 + bx +c = 0\]
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.0
It is possible to figure out this formula by solving that quadratic equation using the method of completing the squares. It is also interesting to note some small things about the formula that may help remember it easier: \(\displaystyle x = \frac{b}{2a} \pm \frac{\sqrt{b^2 4ac}}{2a} \) The first term is the vertex xvalue. This formula in a sense says that the two roots are a distance of \(\displaystyle \frac{\sqrt{b^2  4ac}}{2a}\) from the vertex, in position on the xaxis. (I mean, the horizontal distance) The discriminant portion \(b^2  4ac\) can also be used as a sort of shortcut to figure out more about the roots you'll find. It is under a square root, so we can tell that only nonnegative values give real solutions. If it is zero, then we see that we are adding + 0 to the vertex; i.e., the vertex is also the one root.
 one year ago
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