Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

  • DLS

A sample of milk diluted with water has a density 1032 kg/m^3..if pure milk has a density of 1080 kg/m^3..find %of water by volume in milk!

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
  • DLS
  • DLS
kal test hai and this is the first question!!tell me something atleast :/!
consider total volume to be X let y amt be milk.. then x-y amt is water..

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

final density = total mass/total volume
let milk mass be Mm, let water mass be Mw, then total mass M=Mw + Mm and total volume = x =>1032 = Mw + Mm /x also, 1080 = Mm/y and D = Mw/(x-y)
From last eqn, y=x- (Mw /D) putting that in eqn above that, Mm= ( x -(Mw/D) )*1080 putting this in 1st eqn, 1032 = (Mw/x) + (x- (Mw/D)*1080 No idea after this :P
We might well have to take same approximations at this point of time.

Not the answer you are looking for?

Search for more explanations.

Ask your own question