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miley23

  • 3 years ago

Find the value of cos θ for the angle shown.

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  1. BluFoot
    • 3 years ago
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    We're missing the drawing!

  2. hba
    • 3 years ago
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    Is it involved with Vectors ?

  3. miley23
    • 3 years ago
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  4. hba
    • 3 years ago
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    \[Cos \theta= B/H\]

  5. miley23
    • 3 years ago
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    how do i solve for the answer

  6. BluFoot
    • 3 years ago
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    This is how I would do it. cos(ø) = cos(-ø) So the cos of the smaller angle in the clockwise direction is the same as the big angle in the counterclockwise direction. cos = adjacent / hypotenuse adjacent = 4 and hypotenuse you can find through pythagorus. There's probably an easier way...

  7. miley23
    • 3 years ago
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    so its cos θ = 4/7

  8. BluFoot
    • 3 years ago
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    Yup!

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