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BluFoot Group TitleBest ResponseYou've already chosen the best response.0
We're missing the drawing!
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Is it involved with Vectors ?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
\[Cos \theta= B/H\]
 one year ago

miley23 Group TitleBest ResponseYou've already chosen the best response.0
how do i solve for the answer
 one year ago

BluFoot Group TitleBest ResponseYou've already chosen the best response.0
This is how I would do it. cos(ø) = cos(ø) So the cos of the smaller angle in the clockwise direction is the same as the big angle in the counterclockwise direction. cos = adjacent / hypotenuse adjacent = 4 and hypotenuse you can find through pythagorus. There's probably an easier way...
 one year ago

miley23 Group TitleBest ResponseYou've already chosen the best response.0
so its cos θ = 4/7
 one year ago
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