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roadjester

  • 3 years ago

How do I solve this isobaric differential equation? \[\large ydx + (2x^2y+x)dy=0\]

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  1. roadjester
    • 3 years ago
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    \[\large ydx + (2x^2y+x)dy=0\]

  2. sirm3d
    • 3 years ago
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    this is bernoulli equation in the dependent variable x. \[yx'+x=-2x^2y\\x'+\frac{1}{y}x=-2x^2\]

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