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A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?
 one year ago
 one year ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?
 one year ago
 one year ago

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tomoBest ResponseYou've already chosen the best response.0
thank you. that makes sense. 1/total. However, I am now trying to find the P(correct on 3rd try). Is that P(wrong) * P(wrong) * P(right). if so is that (n1)/n * (n1)/(n1) * 1/(n2)?
 one year ago

tomoBest ResponseYou've already chosen the best response.0
on the second term i mean n2/n1
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
Assuming we can't repeat passwords, that looks correct.
 one year ago

tomoBest ResponseYou've already chosen the best response.0
ok, so extrapolating to (if i <n, on the ith try). I think that it should be something like ((n1)^(i1) * 1)/ (n*(n1)...(ni)). I can't remember what the formula for the sum of products is though.
 one year ago

tomoBest ResponseYou've already chosen the best response.0
actually on the last term of the denominator i think it would be n(i1)
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
I've got to go now, but you certainly could extrapolate like that. To write it exactly, you could do a lot of canceling, or you could write it in product notation using this symbol. \[\prod\]
 one year ago

tomoBest ResponseYou've already chosen the best response.0
thank you very much KingGeorge.
 one year ago
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