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 one year ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?
 one year ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?

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tomo
 one year ago
Best ResponseYou've already chosen the best response.0thank you. that makes sense. 1/total. However, I am now trying to find the P(correct on 3rd try). Is that P(wrong) * P(wrong) * P(right). if so is that (n1)/n * (n1)/(n1) * 1/(n2)?

tomo
 one year ago
Best ResponseYou've already chosen the best response.0on the second term i mean n2/n1

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.1Assuming we can't repeat passwords, that looks correct.

tomo
 one year ago
Best ResponseYou've already chosen the best response.0ok, so extrapolating to (if i <n, on the ith try). I think that it should be something like ((n1)^(i1) * 1)/ (n*(n1)...(ni)). I can't remember what the formula for the sum of products is though.

tomo
 one year ago
Best ResponseYou've already chosen the best response.0actually on the last term of the denominator i think it would be n(i1)

KingGeorge
 one year ago
Best ResponseYou've already chosen the best response.1I've got to go now, but you certainly could extrapolate like that. To write it exactly, you could do a lot of canceling, or you could write it in product notation using this symbol. \[\prod\]

tomo
 one year ago
Best ResponseYou've already chosen the best response.0thank you very much KingGeorge.
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