A community for students.
Here's the question you clicked on:
 0 viewing
tomo
 2 years ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?
tomo
 2 years ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?

This Question is Closed

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0thank you. that makes sense. 1/total. However, I am now trying to find the P(correct on 3rd try). Is that P(wrong) * P(wrong) * P(right). if so is that (n1)/n * (n1)/(n1) * 1/(n2)?

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0on the second term i mean n2/n1

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1Assuming we can't repeat passwords, that looks correct.

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0ok, so extrapolating to (if i <n, on the ith try). I think that it should be something like ((n1)^(i1) * 1)/ (n*(n1)...(ni)). I can't remember what the formula for the sum of products is though.

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0actually on the last term of the denominator i think it would be n(i1)

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.1I've got to go now, but you certainly could extrapolate like that. To write it exactly, you could do a lot of canceling, or you could write it in product notation using this symbol. \[\prod\]

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0thank you very much KingGeorge.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.