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anonymous
 3 years ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?
anonymous
 3 years ago
A computer has a list of n possible passwords. If only one is accepted, what is the probability of guessing the password right on the first try?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you. that makes sense. 1/total. However, I am now trying to find the P(correct on 3rd try). Is that P(wrong) * P(wrong) * P(right). if so is that (n1)/n * (n1)/(n1) * 1/(n2)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0on the second term i mean n2/n1

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Assuming we can't repeat passwords, that looks correct.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, so extrapolating to (if i <n, on the ith try). I think that it should be something like ((n1)^(i1) * 1)/ (n*(n1)...(ni)). I can't remember what the formula for the sum of products is though.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0actually on the last term of the denominator i think it would be n(i1)

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1I've got to go now, but you certainly could extrapolate like that. To write it exactly, you could do a lot of canceling, or you could write it in product notation using this symbol. \[\prod\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you very much KingGeorge.
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