Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

adam32885 Group Title

lim as t approaches 1 ((t^4-1)/(t^3-1)

  • one year ago
  • one year ago

  • This Question is Closed
  1. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you know L'Hopital's rule yet?

    • one year ago
  2. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    no not yet

    • one year ago
  3. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Ok Well you can proceed this way: You want to try and get rid of as many powers as you can. Why not try dividing the numerator and denominator by t^3?

    • one year ago
  4. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I know i need to factor the top and bottom but i am drawing a blank on factoring

    • one year ago
  5. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh duh so it would t-1?

    • one year ago
  6. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh wait that doesn't help sorry. I'm so used of thinking of limits going to infinity

    • one year ago
  7. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Ok Yes I suppose factoring is another way

    • one year ago
  8. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    that is where we are currently at is trying to factor them out

    • one year ago
  9. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Ok t^4-1 is easy to factor. If you think of letting t^2 = x, then you get (x^2-1) which is easily factorable.

    • one year ago
  10. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    t^3-1 is a bit trickier. Do you remember that one way to this is to try finding all factors of your constant term (here it's -1) and plugging it into t^3-1 and see which ones give you zero. This number (say "a") will then be a factor of the form (t-a). Then, you can use long polynomial division to find out the other factor by dividing t^3-1 with (t-a)

    • one year ago
  11. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok gotcha thank you

    • one year ago
  12. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Let me know if you are still stuck after :)

    • one year ago
  13. adam32885 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i will thanks again

    • one year ago
  14. kirbykirby Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    np

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.