Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Waynex

  • one year ago

On the supplemental problems for pset 8, question 4A-4, it says the force field has a magnitude of k/r. The "expression" for this force field has the scalar multiplier k/r^2. I don't understand the reasoning for r to become r^2 when k stays the same.

  • This Question is Closed
  1. Waynex
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    <-y,x> has a magnitude of: \[y ^{2}+x ^{2}.\] And that magnitude is an equation for a circle. So we can represent that magnitude by \[r ^{2}.\] In order to scale that magnitude to the required magnitude of:\[\frac{ 1 }{ r },\] we need to multiply the vector <-y,x> by \[\frac{ 1 }{ r ^{2} }.\]

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.