A community for students.
Here's the question you clicked on:
 0 viewing
Waynex
 3 years ago
On the supplemental problems for pset 8, question 4A4, it says the force field has a magnitude of k/r. The "expression" for this force field has the scalar multiplier k/r^2. I don't understand the reasoning for r to become r^2 when k stays the same.
Waynex
 3 years ago
On the supplemental problems for pset 8, question 4A4, it says the force field has a magnitude of k/r. The "expression" for this force field has the scalar multiplier k/r^2. I don't understand the reasoning for r to become r^2 when k stays the same.

This Question is Closed

Waynex
 3 years ago
Best ResponseYou've already chosen the best response.0<y,x> has a magnitude of: \[y ^{2}+x ^{2}.\] And that magnitude is an equation for a circle. So we can represent that magnitude by \[r ^{2}.\] In order to scale that magnitude to the required magnitude of:\[\frac{ 1 }{ r },\] we need to multiply the vector <y,x> by \[\frac{ 1 }{ r ^{2} }.\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.