## kdarnell08 Group Title solve the square root of 6x+1 = x-1 one year ago one year ago

• This Question is Open
1. kdarnell08 Group Title

|dw:1358734970247:dw|

2. CalebBeavers Group Title

Ok so first square both sides to eliminate the square root

3. kdarnell08 Group Title

what do you mean square both sides...

4. CalebBeavers Group Title

like this $\large \sqrt{6x+1}^{2}=(x-1)^{2}$ on the left hand side the square root and square cancel so youve got $6x+1=(x-1)^{2}$

5. kdarnell08 Group Title

k

6. CalebBeavers Group Title

Ok so now expand the right side

7. kdarnell08 Group Title

k

8. satellite73 Group Title

you got this?

9. CalebBeavers Group Title

Whataya have after you expand the right side of the equation?

10. CalebBeavers Group Title

$6x+1=(x-1)^{2}$ $6x+1=x^{2}-2x+1$ $x^{2}-8x=0$ $x(x-8)=0$ $x=0$ and $x=8$ check for extraneous solutions $\sqrt{6(0)+1}\neq 0-1$ $\sqrt{6(8)+1}=8-1$ $\sqrt{49}=7$ so solution is x=8