## anonymous 3 years ago solve the square root of 6x+1 = x-1

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1. anonymous

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2. anonymous

Ok so first square both sides to eliminate the square root

3. anonymous

what do you mean square both sides...

4. anonymous

like this $\large \sqrt{6x+1}^{2}=(x-1)^{2}$ on the left hand side the square root and square cancel so youve got $6x+1=(x-1)^{2}$

5. anonymous

k

6. anonymous

Ok so now expand the right side

7. anonymous

k

8. anonymous

you got this?

9. anonymous

Whataya have after you expand the right side of the equation?

10. anonymous

$6x+1=(x-1)^{2}$ $6x+1=x^{2}-2x+1$ $x^{2}-8x=0$ $x(x-8)=0$ $x=0$ and $x=8$ check for extraneous solutions $\sqrt{6(0)+1}\neq 0-1$ $\sqrt{6(8)+1}=8-1$ $\sqrt{49}=7$ so solution is x=8