• anonymous
in what order are you supposed to solve matrices (like of linear systems) in a way that does that mess up the earlier steps?!!!!!!!!!!! omg
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • schrodinger
I got my questions answered at in under 10 minutes. Go to now for free help!
  • anonymous
do you have an example?
  • kirbykirby
I'm not entirely sure what you mean, but the general procedure to do is 1) start with the first row and divide the row by the number in the first column (to get a leading 1) 2) Add and substract multiples of rows to the first row in order to get 0 in the first column (except for the leading 1) 3) Same as step 2 but you work on the second column and the second row (this element needs to become a leading one). 4) Add/subtract multiples of rows to the 2nd row to get 0's there (except for the leading 1)... and continue to get a leading one in the 3rd column/3rd row entry etc.. If the 2nd column/2nd row entry has a zero (you cannot make it into a leading one) then just skip that column, and go to the next one and stay on the same row

Looking for something else?

Not the answer you are looking for? Search for more explanations.