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baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358744328225:dw

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0just have to set it up, don't have to actually integrate it. :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2x(x^61) =x(x^3+1)(x^31)

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE{\int\limits \frac{ 1 }{ x^7  x }dx}\]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1dw:1358744642346:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2do you know general formulas for a^3+b^3 and a^3b^3..

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0so how would this spit into partials?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2if there is quadratic equation in denominator, which cannot be factorized, then in numerator, it'll be linear expression, Ax+B...

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1For x^31 and x^3+1 you can use Long polynomial division by finding a factor (xa) where a is a root of the polynomial

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so, whats x^3+1=... ? x^31=.... ?

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1I never learnt the general formula for a^3+b^3. I think it's easier to do polynomial division because it will work for higher powers

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0x^3 +1 = (x+1)(x^2x+1)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so, above x^2x+1 will come a linear expression like Ax+B and above linear terms like x, x(x+1), constants like C,D,E ... will come.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0@kirbykirby polynomial division of what and what?

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0x^3 1 = (x1)(x^2+x+1)

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0okay, i'll try this

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so, you have 5 factors, out of which 2 is quadratic.

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1for x^3+1, you find the factors of the constant (here, its 1) and find which one = 0 when you plug it into your xterms. So, 1 works: ((1)^3+1) = 0. So, the factor that divides the polynomial is always of the form (xa). So, (x(1)) = (x+1). Then divide x^3+1 into x+1

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358745155474:dw

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0@kirbykirby that is useful to know rather than memorizing these formulas.

baldymcgee6
 one year ago
Best ResponseYou've already chosen the best response.0thanks for the help guys!

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1It's often called the "Factor Theorem". http://en.wikipedia.org/wiki/Factor_theorem
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