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|dw:1358744328225:dw|

x^7

just have to set it up, don't have to actually integrate it. :)

x(x^6-1)
=x(x^3+1)(x^3-1)

\[\LARGE{\int\limits \frac{ 1 }{ x^7 - x }dx}\]

|dw:1358744642346:dw|

do you know general formulas for a^3+b^3 and a^3-b^3..

yes

so how would this spit into partials?

so, whats x^3+1=... ?
x^3-1=.... ?

x^3 +1 = (x+1)(x^2-x+1)

@kirbykirby polynomial division of what and what?

x^3 -1 = (x-1)(x^2+x+1)

okay, i'll try this

so, you have 5 factors, out of which 2 is quadratic.

|dw:1358745155474:dw|

\(\checkmark \)

@kirbykirby that is useful to know rather than memorizing these formulas.

thanks for the help guys!

No problem :)

It's often called the "Factor Theorem". http://en.wikipedia.org/wiki/Factor_theorem