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baldymcgee6Best ResponseYou've already chosen the best response.0
dw:1358744328225:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
just have to set it up, don't have to actually integrate it. :)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
x(x^61) =x(x^3+1)(x^31)
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
\[\LARGE{\int\limits \frac{ 1 }{ x^7  x }dx}\]
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
dw:1358744642346:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
do you know general formulas for a^3+b^3 and a^3b^3..
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
so how would this spit into partials?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
if there is quadratic equation in denominator, which cannot be factorized, then in numerator, it'll be linear expression, Ax+B...
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
For x^31 and x^3+1 you can use Long polynomial division by finding a factor (xa) where a is a root of the polynomial
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
so, whats x^3+1=... ? x^31=.... ?
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
I never learnt the general formula for a^3+b^3. I think it's easier to do polynomial division because it will work for higher powers
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
x^3 +1 = (x+1)(x^2x+1)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
so, above x^2x+1 will come a linear expression like Ax+B and above linear terms like x, x(x+1), constants like C,D,E ... will come.
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
@kirbykirby polynomial division of what and what?
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
x^3 1 = (x1)(x^2+x+1)
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
okay, i'll try this
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
so, you have 5 factors, out of which 2 is quadratic.
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
for x^3+1, you find the factors of the constant (here, its 1) and find which one = 0 when you plug it into your xterms. So, 1 works: ((1)^3+1) = 0. So, the factor that divides the polynomial is always of the form (xa). So, (x(1)) = (x+1). Then divide x^3+1 into x+1
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
dw:1358745155474:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
@kirbykirby that is useful to know rather than memorizing these formulas.
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
thanks for the help guys!
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
It's often called the "Factor Theorem". http://en.wikipedia.org/wiki/Factor_theorem
 one year ago
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