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baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358744328225:dw

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0just have to set it up, don't have to actually integrate it. :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2x(x^61) =x(x^3+1)(x^31)

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE{\int\limits \frac{ 1 }{ x^7  x }dx}\]

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1358744642346:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2do you know general formulas for a^3+b^3 and a^3b^3..

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0so how would this spit into partials?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2if there is quadratic equation in denominator, which cannot be factorized, then in numerator, it'll be linear expression, Ax+B...

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1For x^31 and x^3+1 you can use Long polynomial division by finding a factor (xa) where a is a root of the polynomial

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so, whats x^3+1=... ? x^31=.... ?

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1I never learnt the general formula for a^3+b^3. I think it's easier to do polynomial division because it will work for higher powers

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0x^3 +1 = (x+1)(x^2x+1)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so, above x^2x+1 will come a linear expression like Ax+B and above linear terms like x, x(x+1), constants like C,D,E ... will come.

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0@kirbykirby polynomial division of what and what?

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0x^3 1 = (x1)(x^2+x+1)

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0okay, i'll try this

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so, you have 5 factors, out of which 2 is quadratic.

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1for x^3+1, you find the factors of the constant (here, its 1) and find which one = 0 when you plug it into your xterms. So, 1 works: ((1)^3+1) = 0. So, the factor that divides the polynomial is always of the form (xa). So, (x(1)) = (x+1). Then divide x^3+1 into x+1

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358745155474:dw

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0@kirbykirby that is useful to know rather than memorizing these formulas.

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0thanks for the help guys!

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1It's often called the "Factor Theorem". http://en.wikipedia.org/wiki/Factor_theorem
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