Mkid
sqrt[3]{x}^{2}+9=3... Please help!



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mathstudent55
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dw:1358749331314:dw

order
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\[\sqrt{3x^2} + 9 = 3\]\[\sqrt{3x^2}= 39\]\[\sqrt{3x^2}= 6\]\[3x^2 = 6^2\]\[3x^2 = 36\]\[3x= \sqrt{36}\]\[3x=6\]\[Therefore,x=2\]

Mkid
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:D Thank you!

order
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No problem!