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anonymous
 3 years ago
PreCal Help Please!
anonymous
 3 years ago
PreCal Help Please!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Would it be.... \[(3\sqrt{2}\sqrt{10})x(\sqrt{10}+\sqrt{2})y2\sqrt{10}\sqrt{2}=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Hero do you know if I am right? or check to make sure? if not thanks anyways :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0abb0t...thanks for trying to help but that was taken off of yahoo answers and if you continue reading what the person who wrote this said, you will see that none of the answer choices provided were correct. So again thanks, but it doesn't help too much. I just want to know If I go the right answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks and again thanks for trying but I had already seen that post and it didn't help. That is why I posted here.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright this is new to me but this is what It says to do \[3xy=1\] \[x+y=2\] \[(3+1)x+(11)y=2+1\] \[4x=1\] \[x=\frac{1}{4}\] to make sure this is correct test for each for y \[3(\frac{1}{4})y=1\] \[\frac{3}{4}1=y\] \[\frac{7}{4}=y \] \[\frac{1}{4}+y=2\] \[\frac{7}{4}=y\] \[\frac{7}{4}=y\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0intersection point is \[[.25,1.75]\] which is a point on your bisector line also next find the slopes and take the arimetic mean line 1 \[3x1=y\] \[m=3\] \[x+y=2\] \[x2=y\] \[1=m\] \[\frac{1+3}{2}=1\] using that withhin the point slope equation \[yy_1=m(xx_1)\] \[y(1.75)=1(x(.25))\] \[y+1.75=1x+.25\] \[y=1x1.5=x1.5\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358765159547:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks and my answer was right :)
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