## Rosy95 Group Title PreCal Help Please! one year ago one year ago

1. Rosy95 Group Title

Would it be.... $(3\sqrt{2}-\sqrt{10})x-(\sqrt{10}+\sqrt{2})y-2\sqrt{10}-\sqrt{2}=0$

2. Rosy95 Group Title

@Hero do you know if I am right? or check to make sure? if not thanks anyways :)

3. Rosy95 Group Title

abb0t...thanks for trying to help but that was taken off of yahoo answers and if you continue reading what the person who wrote this said, you will see that none of the answer choices provided were correct. So again thanks, but it doesn't help too much. I just want to know If I go the right answer.

4. abb0t Group Title

Best of luck.

5. Rosy95 Group Title

Thanks and again thanks for trying but I had already seen that post and it didn't help. That is why I posted here.

6. Outkast3r09 Group Title

Alright this is new to me but this is what It says to do $3x-y=1$ $x+y=-2$ $(3+1)x+(1-1)y=-2+1$ $4x=-1$ $x=\frac{-1}{4}$ to make sure this is correct test for each for y $3(\frac{-1}{4})-y=1$ $\frac{-3}{4}-1=y$ $\frac{-7}{4}=y$ $\frac{-1}{4}+y=-2$ $\frac{7}{4}=-y$ $\frac{-7}{4}=y$

7. Outkast3r09 Group Title

intersection point is $[-.25,-1.75]$ which is a point on your bisector line also next find the slopes and take the arimetic mean line 1 $3x-1=y$ $m=3$ $x+y=-2$ $-x-2=y$ $-1=m$ $\frac{-1+3}{2}=1$ using that withhin the point slope equation $y-y_1=m(x-x_1)$ $y-(-1.75)=1(x-(-.25))$ $y+1.75=1x+.25$ $y=1x-1.5=x-1.5$

8. Outkast3r09 Group Title

|dw:1358765159547:dw|

9. Rosy95 Group Title

Thanks and my answer was right :)