Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
DLS
Group Title
The rate of flow of a liquid through a tube of length L and radius R is V.Find the rate of flow of liquid through the combination of two tubes of same length L but radii R and R/2 when they are connected in
a)Series
b)parallel
 one year ago
 one year ago
DLS Group Title
The rate of flow of a liquid through a tube of length L and radius R is V.Find the rate of flow of liquid through the combination of two tubes of same length L but radii R and R/2 when they are connected in a)Series b)parallel
 one year ago
 one year ago

This Question is Closed

DLS Group TitleBest ResponseYou've already chosen the best response.0
@shubhamsrg @Yahoo!
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
What does parallel connection mean? Can you draw ?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
not sureanything about this Q
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
The meanings of series and parallel arrangements of pipes is similar to that of electrical components.I have drawn a visual of it in the file attached. The two ends are at some pressure P. A beautiful parallel can be drawn between series and parallel arrangements of resistors and pipes. This is possible by Poisseuille's formula for rate of flow V=(pi*P*r^4)/8*n*l r is radius of cross section n is viscosity l is length of tube This can be simplified using (pi*r^4)8*n*l = C, a constant So V=CP When we draw an analogue between resistor arrangement, we can take V=some sort of current, P=some sort of potential difference and 1/C = R =resistance to the flow Although we can do the process step by step , it is easier to use the same results of resistor arrangement. Only the important thing is that volume flow (current) is same in both tubes (resistors) in series. And pressure difference (potential difference) is same across both tubes in parallel. 1) In series total resistance R=R1+R2 = (33*8*n*l)/pi*R^4 volume flow=P/R=(pi*P*R^4)/8*33*n*l = V/33 2) In parallel 1/R= 1/R1+1/R2 R=8*n*l/33*pi*R^4 You will find the flow to be 33V
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
Its gonna take me time to grasp all.
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
i got my ans and i t was easy :P that guy did it wrong
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
Please post it here, Its very rare that @Diwakar does it wrong.
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
What are the correct answers?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
V/17 for series and 17V/16 for parallel
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
Of course, i made a grave mistake in calculations. I took 2^4=32. Sorry for that!!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.