Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

DLS

  • 2 years ago

The rate of flow of a liquid through a tube of length L and radius R is V.Find the rate of flow of liquid through the combination of two tubes of same length L but radii R and R/2 when they are connected in a)Series b)parallel

  • This Question is Closed
  1. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @shubhamsrg @Yahoo!

  2. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2

  3. shubhamsrg
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What does parallel connection mean? Can you draw ?

  4. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    not sureanything about this Q

  5. Diwakar
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The meanings of series and parallel arrangements of pipes is similar to that of electrical components.I have drawn a visual of it in the file attached. The two ends are at some pressure P. A beautiful parallel can be drawn between series and parallel arrangements of resistors and pipes. This is possible by Poisseuille's formula for rate of flow V=(pi*P*r^4)/8*n*l r is radius of cross section n is viscosity l is length of tube This can be simplified using (pi*r^4)8*n*l = C, a constant So V=CP When we draw an analogue between resistor arrangement, we can take V=some sort of current, P=some sort of potential difference and 1/C = R =resistance to the flow Although we can do the process step by step , it is easier to use the same results of resistor arrangement. Only the important thing is that volume flow (current) is same in both tubes (resistors) in series. And pressure difference (potential difference) is same across both tubes in parallel. 1) In series total resistance R=R1+R2 = (33*8*n*l)/pi*R^4 volume flow=P/R=(pi*P*R^4)/8*33*n*l = V/33 2) In parallel 1/R= 1/R1+1/R2 R=8*n*l/33*pi*R^4 You will find the flow to be 33V

    1 Attachment
  6. shubhamsrg
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Its gonna take me time to grasp all.

  7. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got my ans and i t was easy :P that guy did it wrong

  8. shubhamsrg
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please post it here, Its very rare that @Diwakar does it wrong.

  9. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    P=P1+P2 :o

  10. Diwakar
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What are the correct answers?

  11. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    V/17 for series and 17V/16 for parallel

  12. Diwakar
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Of course, i made a grave mistake in calculations. I took 2^4=32. Sorry for that!!

  13. DLS
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :)

  14. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.