DLS
  • DLS
The rate of flow of a liquid through a tube of length L and radius R is V.Find the rate of flow of liquid through the combination of two tubes of same length L but radii R and R/2 when they are connected in a)Series b)parallel
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DLS
  • DLS
@shubhamsrg @Yahoo!
DLS
  • DLS
2
shubhamsrg
  • shubhamsrg
What does parallel connection mean? Can you draw ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

DLS
  • DLS
not sureanything about this Q
anonymous
  • anonymous
The meanings of series and parallel arrangements of pipes is similar to that of electrical components.I have drawn a visual of it in the file attached. The two ends are at some pressure P. A beautiful parallel can be drawn between series and parallel arrangements of resistors and pipes. This is possible by Poisseuille's formula for rate of flow V=(pi*P*r^4)/8*n*l r is radius of cross section n is viscosity l is length of tube This can be simplified using (pi*r^4)8*n*l = C, a constant So V=CP When we draw an analogue between resistor arrangement, we can take V=some sort of current, P=some sort of potential difference and 1/C = R =resistance to the flow Although we can do the process step by step , it is easier to use the same results of resistor arrangement. Only the important thing is that volume flow (current) is same in both tubes (resistors) in series. And pressure difference (potential difference) is same across both tubes in parallel. 1) In series total resistance R=R1+R2 = (33*8*n*l)/pi*R^4 volume flow=P/R=(pi*P*R^4)/8*33*n*l = V/33 2) In parallel 1/R= 1/R1+1/R2 R=8*n*l/33*pi*R^4 You will find the flow to be 33V
1 Attachment
shubhamsrg
  • shubhamsrg
Its gonna take me time to grasp all.
DLS
  • DLS
i got my ans and i t was easy :P that guy did it wrong
shubhamsrg
  • shubhamsrg
Please post it here, Its very rare that @Diwakar does it wrong.
DLS
  • DLS
P=P1+P2 :o
anonymous
  • anonymous
What are the correct answers?
DLS
  • DLS
V/17 for series and 17V/16 for parallel
anonymous
  • anonymous
Of course, i made a grave mistake in calculations. I took 2^4=32. Sorry for that!!
DLS
  • DLS
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.