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A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal.
If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.
 one year ago
 one year ago
A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal. If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.
 one year ago
 one year ago

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thushananth01Best ResponseYou've already chosen the best response.0
dw:1358779489492:dw
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
@Hero @Preetha @ghazi @AravindG
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
I think I saw a similiar question in NCERT text chapter 11 under topic of Young's modulus and all..take a look
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
can u give me the link of the book?
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
you are not from India?
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
i suggest you google it..its easy to get NCERT CLASS 11 PHYSICS PART 2
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
do they have the solutions
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
infact the book is very nice for reference
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
http://www.vidhyarjan.com/news/ncertsolutionsforclass11physics
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
http://ncertbooks.prashanthellina.com/11_Physics.html
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
can u change the language?
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
ofcourse eng is below scroll down
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
the question isnt there
 one year ago

MashyBest ResponseYou've already chosen the best response.1
Ok.. so since the xy is horizontal.. it means after stretching, both the bars have exactly the same length.. so i can say \[l1+\Delta l1 = l2 + \Delta l2 \] next step we find the stress that is coming on each of them.. that should be easy.. since the ration of ox: oy is given to us..
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
can u show the working please:)
 one year ago

MashyBest ResponseYou've already chosen the best response.1
try doing it :P.. first you tell me how much will be the stress that comes on X and Y ?
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
stress = force/ area how do i distrbte the force
 one year ago

MashyBest ResponseYou've already chosen the best response.1
first find the force.. force equals the weight that each one would experience.. the weight is at a ratio of 2:1 .. hence the distribution will be in inverse ratio right? 1:2.. cause if weight is far away, its effect is smaller!
 one year ago

MashyBest ResponseYou've already chosen the best response.1
so now calculate Fx and Fy
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
Fx = 2/3 Fy Fy = 1/3 Fx ?
 one year ago

MashyBest ResponseYou've already chosen the best response.1
total force is known to you.. so find the ratios now!
 one year ago

MashyBest ResponseYou've already chosen the best response.1
Fx = 2/3 Ftotal :P and Fy = 1/3 Ftotal
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
Fx = 20N and Fy = 10N
 one year ago

MashyBest ResponseYou've already chosen the best response.1
ok.. :D.. next.. find the stress on X and since young's modulus of X is given.. find the strain.. Similarly do the same thing for Y.. but young's modulus is not given.. divide the two equations to get rid of A
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
thanks alot Strain = F/A*E1 strain in X = 20/A* 1.0 * 10^11 strain is equal so E2 = stress/ strain E2 = 10/A *A*1.0*10^11/20 E2 = 5 * 10^11 pa
 one year ago

MashyBest ResponseYou've already chosen the best response.1
woah wait.. how did you get the strain for Y ?
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
arent they equal
 one year ago

MashyBest ResponseYou've already chosen the best response.1
nope :/.. why would the strains be equal?
 one year ago

MashyBest ResponseYou've already chosen the best response.1
now you have to use the first equatoin.. that i put.. but use lx and ly notation instead of l1 and l2 notation
 one year ago

MashyBest ResponseYou've already chosen the best response.1
they are NOT SAME MATERIAL.. IF THEY WERE.. THEY WOULD HAVE SAME YOUNG"S MODULUS :P
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
i dont undrstnd >< cn u shw the working
 one year ago

MashyBest ResponseYou've already chosen the best response.1
use the first equation .. try doing it.. see you need to get rid of \[\Delta ly/ ly\] in that equation i asked you to build by dividing the two equations
 one year ago

MashyBest ResponseYou've already chosen the best response.1
so here are the two equations \[Fx / Fy = Ex \Delta x ly / Ey \Delta ylx \] and \[lx + \Delta x = ly + \Delta y\] somehow use them
 one year ago

thushananth01Best ResponseYou've already chosen the best response.0
ok il use thnks fr ur help :)
 one year ago
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