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 one year ago
A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal.
If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.
 one year ago
A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal. If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.

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thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358779489492:dw

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0@Hero @Preetha @ghazi @AravindG

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0I think I saw a similiar question in NCERT text chapter 11 under topic of Young's modulus and all..take a look

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0can u give me the link of the book?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0you are not from India?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0i suggest you google it..its easy to get NCERT CLASS 11 PHYSICS PART 2

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0do they have the solutions

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0infact the book is very nice for reference

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0http://www.vidhyarjan.com/news/ncertsolutionsforclass11physics

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0can u change the language?

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0ofcourse eng is below scroll down

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0the question isnt there

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1Ok.. so since the xy is horizontal.. it means after stretching, both the bars have exactly the same length.. so i can say \[l1+\Delta l1 = l2 + \Delta l2 \] next step we find the stress that is coming on each of them.. that should be easy.. since the ration of ox: oy is given to us..

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0can u show the working please:)

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1try doing it :P.. first you tell me how much will be the stress that comes on X and Y ?

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0stress = force/ area how do i distrbte the force

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1first find the force.. force equals the weight that each one would experience.. the weight is at a ratio of 2:1 .. hence the distribution will be in inverse ratio right? 1:2.. cause if weight is far away, its effect is smaller!

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1so now calculate Fx and Fy

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0Fx = 2/3 Fy Fy = 1/3 Fx ?

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1total force is known to you.. so find the ratios now!

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1Fx = 2/3 Ftotal :P and Fy = 1/3 Ftotal

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0Fx = 20N and Fy = 10N

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1ok.. :D.. next.. find the stress on X and since young's modulus of X is given.. find the strain.. Similarly do the same thing for Y.. but young's modulus is not given.. divide the two equations to get rid of A

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0thanks alot Strain = F/A*E1 strain in X = 20/A* 1.0 * 10^11 strain is equal so E2 = stress/ strain E2 = 10/A *A*1.0*10^11/20 E2 = 5 * 10^11 pa

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1woah wait.. how did you get the strain for Y ?

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0arent they equal

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1nope :/.. why would the strains be equal?

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1now you have to use the first equatoin.. that i put.. but use lx and ly notation instead of l1 and l2 notation

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1they are NOT SAME MATERIAL.. IF THEY WERE.. THEY WOULD HAVE SAME YOUNG"S MODULUS :P

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0i dont undrstnd >< cn u shw the working

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1use the first equation .. try doing it.. see you need to get rid of \[\Delta ly/ ly\] in that equation i asked you to build by dividing the two equations

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1so here are the two equations \[Fx / Fy = Ex \Delta x ly / Ey \Delta ylx \] and \[lx + \Delta x = ly + \Delta y\] somehow use them

thushananth01
 one year ago
Best ResponseYou've already chosen the best response.0ok il use thnks fr ur help :)
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