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thushananth01

  • one year ago

A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and cross-sectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal. If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.

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  1. thushananth01
    • one year ago
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    |dw:1358779489492:dw|

  2. thushananth01
    • one year ago
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    @Hero @Preetha @ghazi @AravindG

  3. AravindG
    • one year ago
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    I think I saw a similiar question in NCERT text chapter 11 under topic of Young's modulus and all..take a look

  4. thushananth01
    • one year ago
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    can u give me the link of the book?

  5. AravindG
    • one year ago
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    you are not from India?

  6. thushananth01
    • one year ago
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    nope

  7. AravindG
    • one year ago
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    i suggest you google it..its easy to get NCERT CLASS 11 PHYSICS PART 2

  8. thushananth01
    • one year ago
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    do they have the solutions

  9. AravindG
    • one year ago
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    yes i think .....

  10. AravindG
    • one year ago
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    worth checking

  11. AravindG
    • one year ago
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    infact the book is very nice for reference

  12. thushananth01
    • one year ago
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    http://www.vidhyarjan.com/news/ncert-solutions-for-class-11-physics

  13. AravindG
    • one year ago
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    http://ncertbooks.prashanthellina.com/11_Physics.html

  14. thushananth01
    • one year ago
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    can u change the language?

  15. AravindG
    • one year ago
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    ofcourse eng is below scroll down

  16. AravindG
    • one year ago
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    gt it?

  17. thushananth01
    • one year ago
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    the question isnt there

  18. Mashy
    • one year ago
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    Ok.. so since the xy is horizontal.. it means after stretching, both the bars have exactly the same length.. so i can say \[l1+\Delta l1 = l2 + \Delta l2 \] next step we find the stress that is coming on each of them.. that should be easy.. since the ration of ox: oy is given to us..

  19. thushananth01
    • one year ago
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    can u show the working please:)

  20. Mashy
    • one year ago
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    try doing it :P.. first you tell me how much will be the stress that comes on X and Y ?

  21. thushananth01
    • one year ago
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    stress = force/ area how do i distrbte the force

  22. Mashy
    • one year ago
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    first find the force.. force equals the weight that each one would experience.. the weight is at a ratio of 2:1 .. hence the distribution will be in inverse ratio right? 1:2.. cause if weight is far away, its effect is smaller!

  23. Mashy
    • one year ago
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    hence Fx : Fy = 2:1

  24. Mashy
    • one year ago
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    so now calculate Fx and Fy

  25. thushananth01
    • one year ago
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    Fx = 2/3 Fy Fy = 1/3 Fx ?

  26. Mashy
    • one year ago
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    total force is known to you.. so find the ratios now!

  27. Mashy
    • one year ago
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    Fx = 2/3 Ftotal :P and Fy = 1/3 Ftotal

  28. thushananth01
    • one year ago
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    Fx = 20N and Fy = 10N

  29. Mashy
    • one year ago
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    ok.. :D.. next.. find the stress on X and since young's modulus of X is given.. find the strain.. Similarly do the same thing for Y.. but young's modulus is not given.. divide the two equations to get rid of A

  30. thushananth01
    • one year ago
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    thanks alot Strain = F/A*E1 strain in X = 20/A* 1.0 * 10^11 strain is equal so E2 = stress/ strain E2 = 10/A *A*1.0*10^11/20 E2 = 5 * 10^11 pa

  31. Mashy
    • one year ago
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    woah wait.. how did you get the strain for Y ?

  32. thushananth01
    • one year ago
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    arent they equal

  33. Mashy
    • one year ago
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    nope :-/.. why would the strains be equal?

  34. thushananth01
    • one year ago
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    same mterial

  35. Mashy
    • one year ago
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    now you have to use the first equatoin.. that i put.. but use lx and ly notation instead of l1 and l2 notation

  36. Mashy
    • one year ago
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    they are NOT SAME MATERIAL.. IF THEY WERE.. THEY WOULD HAVE SAME YOUNG"S MODULUS :P

  37. thushananth01
    • one year ago
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    i dont undrstnd >< cn u shw the working

  38. Mashy
    • one year ago
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    use the first equation .. try doing it.. see you need to get rid of \[\Delta ly/ ly\] in that equation i asked you to build by dividing the two equations

  39. Mashy
    • one year ago
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    so here are the two equations \[Fx / Fy = Ex \Delta x ly / Ey \Delta ylx \] and \[lx + \Delta x = ly + \Delta y\] somehow use them

  40. thushananth01
    • one year ago
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    ok il use thnks fr ur help :)

  41. Mashy
    • one year ago
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    No problimo amigo :D

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