A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal.
If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.
 2 years ago
A uniform steel wire X and Y, suspended at the same horizontal level, are connected by a light and crosssectional area A, A weight of 30 N is placed at O, on the road OX : OY = 1 : 2. Both wires are stretched and the rod XY then remains horizontal. If he wire X has a young modulus E1 of 1.0 * 10^11 pa, calculate the yound modulus of E2 of the wire Y assuming the elastic limit is not exceeded for both wires.

This Question is Closed

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358779489492:dw

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0@Hero @Preetha @ghazi @AravindG

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0I think I saw a similiar question in NCERT text chapter 11 under topic of Young's modulus and all..take a look

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0can u give me the link of the book?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0you are not from India?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0i suggest you google it..its easy to get NCERT CLASS 11 PHYSICS PART 2

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0do they have the solutions

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0infact the book is very nice for reference

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.vidhyarjan.com/news/ncertsolutionsforclass11physics

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0can u change the language?

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0ofcourse eng is below scroll down

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0the question isnt there

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1Ok.. so since the xy is horizontal.. it means after stretching, both the bars have exactly the same length.. so i can say \[l1+\Delta l1 = l2 + \Delta l2 \] next step we find the stress that is coming on each of them.. that should be easy.. since the ration of ox: oy is given to us..

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0can u show the working please:)

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1try doing it :P.. first you tell me how much will be the stress that comes on X and Y ?

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0stress = force/ area how do i distrbte the force

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1first find the force.. force equals the weight that each one would experience.. the weight is at a ratio of 2:1 .. hence the distribution will be in inverse ratio right? 1:2.. cause if weight is far away, its effect is smaller!

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1so now calculate Fx and Fy

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0Fx = 2/3 Fy Fy = 1/3 Fx ?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1total force is known to you.. so find the ratios now!

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1Fx = 2/3 Ftotal :P and Fy = 1/3 Ftotal

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0Fx = 20N and Fy = 10N

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1ok.. :D.. next.. find the stress on X and since young's modulus of X is given.. find the strain.. Similarly do the same thing for Y.. but young's modulus is not given.. divide the two equations to get rid of A

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0thanks alot Strain = F/A*E1 strain in X = 20/A* 1.0 * 10^11 strain is equal so E2 = stress/ strain E2 = 10/A *A*1.0*10^11/20 E2 = 5 * 10^11 pa

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1woah wait.. how did you get the strain for Y ?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1nope :/.. why would the strains be equal?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1now you have to use the first equatoin.. that i put.. but use lx and ly notation instead of l1 and l2 notation

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1they are NOT SAME MATERIAL.. IF THEY WERE.. THEY WOULD HAVE SAME YOUNG"S MODULUS :P

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0i dont undrstnd >< cn u shw the working

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1use the first equation .. try doing it.. see you need to get rid of \[\Delta ly/ ly\] in that equation i asked you to build by dividing the two equations

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1so here are the two equations \[Fx / Fy = Ex \Delta x ly / Ey \Delta ylx \] and \[lx + \Delta x = ly + \Delta y\] somehow use them

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0ok il use thnks fr ur help :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.