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amistre64Best ResponseYou've already chosen the best response.0
given: \[(p+q)^n\] we can work out the middle stuff as:\[p^{nc}q^c\] the coeeficient is a little tricker unless you know about combinatorics
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
and c is the "term" value :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
n choose c is what i think i recall for the coeff; or else draw up the pascal triangle
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
dw:1358788894374:dw This is the working formula.
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
that looks about right, but if i remember it correctly: the first term starts at 9 and drops down till it hits the 7th term
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
The first term's coefficient is 1 , when r=0,
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
(a+b)^9 a^9 a^8 a^7 a^6 a^5 a^4 a^3 ^^^ b^0 b^1 b^2 .... b^6 ^^^ these always get turned around in my head
 one year ago
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