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kaykim95
HELP!!!!!!!!!!!!!!!!!!! PLEASE!!!!!!!!!!!!!!!!!!! Use properties of logarithms to solve for x
\[2\log_{2} (2x) + \log_{2}8=6 \]
\[\log_{2} 4x ^{2}+\log_{2} 8=6\] \[\log_{2} 32x ^{2}=6\] \[32x ^{2}=2^{6}=64\] We will get two roots of x. We probably neglect the negative root.