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sophiasmommy94Best ResponseYou've already chosen the best response.0
can you help me please?
 one year ago

shreya.Best ResponseYou've already chosen the best response.1
take 6 to the RHS and add the no.s . then square both LHS n RHS. hope it helps..
 one year ago

sophiasmommy94Best ResponseYou've already chosen the best response.0
i don't understand what you mean?
 one year ago

rosedewittbukaterBest ResponseYou've already chosen the best response.1
first add 6 to both sides to get \[\sqrt{2x+10}=8\] Then square both sides to get rid of the square root sign. \[\sqrt{2x+10}^{2}=8^{2}\] Then you will have \[2x+10=64\] Then you have to get x by itself. So subtract 10 from both sides to get \[2x=54\] Finally, divide both sides by 2 to get \[x=27\]
 one year ago

rosedewittbukaterBest ResponseYou've already chosen the best response.1
You can check your work by pluggin back in 27 for x. \[\sqrt{2(27)+10}6=2\] Simplify \[\sqrt{54+10}6=2\] \[\sqrt{64}6=2\] \[86=2\] \[2=2\] Since 2 does equal 2, the solution is correct.
 one year ago

sophiasmommy94Best ResponseYou've already chosen the best response.0
Okay, thank you girls! You both helped out a lot!!
 one year ago
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