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sophiasmommy94

What is the solution to the equation? √2x+10-6 = 2

  • one year ago
  • one year ago

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  1. Mertsj
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    \[\sqrt{2x+10}-6=2\]

    • one year ago
  2. Mertsj
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    Is that the problem?

    • one year ago
  3. sophiasmommy94
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    yeah

    • one year ago
  4. sophiasmommy94
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    can you help me please?

    • one year ago
  5. shreya.
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    take 6 to the RHS and add the no.s . then square both LHS n RHS. hope it helps..

    • one year ago
  6. sophiasmommy94
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    i don't understand what you mean?

    • one year ago
  7. rosedewittbukater
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    first add 6 to both sides to get \[\sqrt{2x+10}=8\] Then square both sides to get rid of the square root sign. \[\sqrt{2x+10}^{2}=8^{2}\] Then you will have \[2x+10=64\] Then you have to get x by itself. So subtract 10 from both sides to get \[2x=54\] Finally, divide both sides by 2 to get \[x=27\]

    • one year ago
  8. shreya.
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    |dw:1358795559725:dw|

    • one year ago
  9. sophiasmommy94
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    so x=27?

    • one year ago
  10. rosedewittbukater
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    You can check your work by pluggin back in 27 for x. \[\sqrt{2(27)+10}-6=2\] Simplify \[\sqrt{54+10}-6=2\] \[\sqrt{64}-6=2\] \[8-6=2\] \[2=2\] Since 2 does equal 2, the solution is correct.

    • one year ago
  11. rosedewittbukater
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    Yes, x=27

    • one year ago
  12. sophiasmommy94
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    Okay, thank you girls! You both helped out a lot!!

    • one year ago
  13. shreya.
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    :) no prob

    • one year ago
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