## Shido88 Group Title Solve for x 83=27^x Consider that: log(a^x)=x (times) log(a) one year ago one year ago

1. abb0t Group Title

It looks like you already have your answer there. So just apply it and solve for x.

2. Mertsj Group Title

$\log(83)=xlog(27)$ $x=\frac{\log(83)}{\log(27)}$

3. Shido88 Group Title

on the log(27) part, do you just ignore the x over the 27 ? or where did it goes ?

4. Mertsj Group Title

That's where the rule comes in. if 8=2^3 then log8=3log2