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Shido88

  • 3 years ago

Solve for x 83=27^x Consider that: log(a^x)=x (times) log(a)

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  1. abb0t
    • 3 years ago
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    It looks like you already have your answer there. So just apply it and solve for x.

  2. Mertsj
    • 3 years ago
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    \[\log(83)=xlog(27)\] \[x=\frac{\log(83)}{\log(27)}\]

  3. Shido88
    • 3 years ago
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    on the log(27) part, do you just ignore the x over the 27 ? or where did it goes ?

  4. Mertsj
    • 3 years ago
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    That's where the rule comes in. if 8=2^3 then log8=3log2

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