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o.o first order ODE :o

I think it has something to do with the solution changing as t->infinity

as t approacs infinity the other two expressions approach zero.

Is it (3/(4t))cos(2t) or (3t/4)cos(2t)?

It is (3/(4t))cos(2t)

\(\large \lim_{t->\inf} (3/2)\sin(2t)+\frac{3}{4t}\cos(2t)+(c/t)\)
\(=(3/2)\sin(2t)+0*\cos(2t)+0\)

Thank you! If I just take the limit as t->infinity, then what is the point of adding that t>0?

I'm not particularly sure either, but I will try to make sense out of it.

Alright, well thank you!

thank you!

you're welcome :)