A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Initially, the block whose mass m = 1.0 kg and the block whose mass is M are both at rest on a frictionless inclined plane at 30 degrees from the ground. The block of mass M rests against a spring that has a spring constant of 11,000 N/m. The distance along the plane between the two blocks is 4.0 m. The block of mass m is released, makes an elastic collision with the block of mass M, and rebounds a distance of 2.56 m back up the inclined plane. The block whose mass is M comes to rest momentarily 4.0 cm from its initial position. Find M.
 one year ago
Initially, the block whose mass m = 1.0 kg and the block whose mass is M are both at rest on a frictionless inclined plane at 30 degrees from the ground. The block of mass M rests against a spring that has a spring constant of 11,000 N/m. The distance along the plane between the two blocks is 4.0 m. The block of mass m is released, makes an elastic collision with the block of mass M, and rebounds a distance of 2.56 m back up the inclined plane. The block whose mass is M comes to rest momentarily 4.0 cm from its initial position. Find M.

This Question is Closed

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1Considering that there is no friction, and there is obvious loss in potential energy of m, and so the energy will be converted to the only available place to store energy, the spring, thus spring potential energy. with that in mind, the total change in mechanical energy(for elastic collision) \(mg \Delta h_1 = \frac{1}{2} k \Delta x^2 +Mg\Delta h_2 \) where \(\Delta h =\Delta d \sin \theta\), assuming that 4cm that M moved is downwards, so, \((1)(9.8)(42.56)(\sin 30^o)=\frac{1}{2}(11000)(0.04)^2 + M(9.8)(0.04)\) find M.

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1sorry, it's \(M(9.8)(0.04)(\sin 30^o)\) for the last term.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.