anonymous
  • anonymous
Initially, the block whose mass m = 1.0 kg and the block whose mass is M are both at rest on a frictionless inclined plane at 30 degrees from the ground. The block of mass M rests against a spring that has a spring constant of 11,000 N/m. The distance along the plane between the two blocks is 4.0 m. The block of mass m is released, makes an elastic collision with the block of mass M, and rebounds a distance of 2.56 m back up the inclined plane. The block whose mass is M comes to rest momentarily 4.0 cm from its initial position. Find M.
Physics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Considering that there is no friction, and there is obvious loss in potential energy of m, and so the energy will be converted to the only available place to store energy, the spring, thus spring potential energy. with that in mind, the total change in mechanical energy(for elastic collision) \(mg \Delta h_1 = \frac{1}{2} k \Delta x^2 +Mg\Delta h_2 \) where \(\Delta h =\Delta d \sin \theta\), assuming that 4cm that M moved is downwards, so, \((1)(9.8)(4-2.56)(\sin 30^o)=\frac{1}{2}(11000)(0.04)^2 + M(9.8)(-0.04)\) find M.
anonymous
  • anonymous
sorry, it's \(M(9.8)(-0.04)(\sin 30^o)\) for the last term.

Looking for something else?

Not the answer you are looking for? Search for more explanations.