Initially, the block whose mass m = 1.0 kg and the block whose mass is M are both at rest on a frictionless inclined plane at 30 degrees from the ground. The block of mass M rests against a spring that has a spring constant of 11,000 N/m. The distance along the plane between the two blocks is 4.0 m. The block of mass m is released, makes an elastic collision with the block of mass M, and rebounds a distance of 2.56 m back up the inclined plane. The block whose mass is M comes to rest momentarily 4.0 cm from its initial position. Find M.

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sorry, it's \(M(9.8)(-0.04)(\sin 30^o)\) for the last term.

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