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ksaimouli

circle

  • one year ago
  • one year ago

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  1. ksaimouli
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    |dw:1358806909531:dw|

    • one year ago
  2. ksaimouli
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    area of circle

    • one year ago
  3. ksaimouli
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    @zepdrix

    • one year ago
  4. Outkast3r09
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    what are you trying to find

    • one year ago
  5. ksaimouli
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    area of that

    • one year ago
  6. zepdrix
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    |dw:1358880151258:dw|Your picture is so sloppy :D Lemme see if this looks correct.

    • one year ago
  7. zepdrix
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    Theta is the angle. s is the letter we use for arc length.

    • one year ago
  8. zepdrix
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    Umm let's first find the radius. I think we're going to need that. Here is a helpful formula:\[\large s=r \theta\]We want to solve for r so let's divide both sides by \(\theta\).\[\large \frac{s}{\theta}=r\]

    • one year ago
  9. zepdrix
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    Our theta is given in degrees, so we'll need to convert it to radians.\[\large 30^o \left(\frac{\pi}{180^o}\right)=\frac{\pi}{6}\] So our radius is given by this,\[\large r=\frac{6\pi}{\left(\dfrac{\pi}{6}\right)}\] Which tells us that we have a radius of 36.

    • one year ago
  10. zepdrix
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    So now we need the area of this sector. Hmm. So it's a percentage of the area of a circle. So it will end up being the same formula we use for area of a circle, just with a fraction in front of it to show that we only want a fraction of that area.\[\large A=\left(C\right)\pi r^2\]From here we just need to find out what C is. You actually probably have a formula on a sheet somewhere, so I likely don't need to go into this much detail :) lol my bad. Anyway, our fraction will be the number of degrees we care about DIVIDED BY the total degrees in a circle.\[\large A=\left(\frac{30^o}{180^o}\right)\pi r^2\]The degree bubbles will cancel out, giving us a unit-less quantity (which is what we want).\[\large A=\left(\frac{1}{6}\right)\pi r^2\]

    • one year ago
  11. zepdrix
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    And we determined earlier that our radius was \(\large r=36\). Plugging this in gives us,\[\large A=\left(\frac{1}{6}\right)\pi (36)^2 \qquad = \qquad \left(\frac{1}{\cancel{6}}\right)\pi (6)^{\cancel{4}3}\]

    • one year ago
  12. zepdrix
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    \[\large A=216\pi\]

    • one year ago
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