## adam32885 Group Title Limit Help lim as x approches -4 ((1/4)+(1/x)/(4+x) one year ago one year ago

Does that make sense or should i draw it?

2. zepdrix Group Title

$\huge \lim_{x \rightarrow -4}\frac{\frac{1}{4}+\frac{1}{x}}{4+x}$ It makes sense c: But I wanted to format it anway, heh.

yes that is it we have only covered limit laws so far.

4. zepdrix Group Title

Ok this one isn't too bad.. it's just to test your silly math skills. So first let's get a common denominator on top.

My "silly" math skills are slowly coming back I took precalc 5 years ago

6. zepdrix Group Title

Remember how to get a common denominator? We'll just multiply them both together, that will be the easiest way to do it. So our common denominator will be 4x. It looks like the first term is missing an x, while the second term is missing a 4, So let's fix that. $\huge \lim_{x \rightarrow -4}\frac{\left(\color{cornflowerblue}{\frac{x}{x}}\cdot \frac{1}{4}\right)+\left(\frac{1}{x}\cdot \color{cornflowerblue}{\frac{4}{4}}\right)}{4+x}$Understand that part ok? :D

7. zepdrix Group Title

$\huge \lim_{x \rightarrow -4}\frac{\left(\frac{4+x}{4x}\right)}{4+x}$

okay so now can the denominator of the whole problem cancel out the numerator on the top leaving 4x?

9. zepdrix Group Title

oh well, um let's be careful a sec :)

10. zepdrix Group Title

We can write our problem like this,$\large \lim_{x \rightarrow -4}\frac{\left(\frac{4+x}{4x}\right)}{4+x} \qquad =\qquad \lim_{x \rightarrow -4} \left(\frac{4+x}{4x}\right)\cdot \frac{1}{4+x}$

11. zepdrix Group Title

Maybe this will help you see what's going on better. So what happens when we cancel those out? :O

it is 1/4x so the lim will be -1/16

13. zepdrix Group Title

Yay good job \c:/