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anonymous
 3 years ago
Limit Help
lim as x approches 4
((1/4)+(1/x)/(4+x)
anonymous
 3 years ago
Limit Help lim as x approches 4 ((1/4)+(1/x)/(4+x)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Does that make sense or should i draw it?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \lim_{x \rightarrow 4}\frac{\frac{1}{4}+\frac{1}{x}}{4+x}\] It makes sense c: But I wanted to format it anway, heh.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes that is it we have only covered limit laws so far.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Ok this one isn't too bad.. it's just to test your silly math skills. So first let's get a common denominator on top.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0My "silly" math skills are slowly coming back I took precalc 5 years ago

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Remember how to get a common denominator? We'll just multiply them both together, that will be the easiest way to do it. So our common denominator will be 4x. It looks like the first term is missing an x, while the second term is missing a 4, So let's fix that. \[\huge \lim_{x \rightarrow 4}\frac{\left(\color{cornflowerblue}{\frac{x}{x}}\cdot \frac{1}{4}\right)+\left(\frac{1}{x}\cdot \color{cornflowerblue}{\frac{4}{4}}\right)}{4+x}\]Understand that part ok? :D

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \lim_{x \rightarrow 4}\frac{\left(\frac{4+x}{4x}\right)}{4+x}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so now can the denominator of the whole problem cancel out the numerator on the top leaving 4x?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1oh well, um let's be careful a sec :)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1We can write our problem like this,\[\large \lim_{x \rightarrow 4}\frac{\left(\frac{4+x}{4x}\right)}{4+x} \qquad =\qquad \lim_{x \rightarrow 4} \left(\frac{4+x}{4x}\right)\cdot \frac{1}{4+x}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Maybe this will help you see what's going on better. So what happens when we cancel those out? :O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is 1/4x so the lim will be 1/16
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