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adam32885 Group TitleBest ResponseYou've already chosen the best response.0
Does that make sense or should i draw it?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \lim_{x \rightarrow 4}\frac{\frac{1}{4}+\frac{1}{x}}{4+x}\] It makes sense c: But I wanted to format it anway, heh.
 one year ago

adam32885 Group TitleBest ResponseYou've already chosen the best response.0
yes that is it we have only covered limit laws so far.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Ok this one isn't too bad.. it's just to test your silly math skills. So first let's get a common denominator on top.
 one year ago

adam32885 Group TitleBest ResponseYou've already chosen the best response.0
My "silly" math skills are slowly coming back I took precalc 5 years ago
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Remember how to get a common denominator? We'll just multiply them both together, that will be the easiest way to do it. So our common denominator will be 4x. It looks like the first term is missing an x, while the second term is missing a 4, So let's fix that. \[\huge \lim_{x \rightarrow 4}\frac{\left(\color{cornflowerblue}{\frac{x}{x}}\cdot \frac{1}{4}\right)+\left(\frac{1}{x}\cdot \color{cornflowerblue}{\frac{4}{4}}\right)}{4+x}\]Understand that part ok? :D
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \lim_{x \rightarrow 4}\frac{\left(\frac{4+x}{4x}\right)}{4+x}\]
 one year ago

adam32885 Group TitleBest ResponseYou've already chosen the best response.0
okay so now can the denominator of the whole problem cancel out the numerator on the top leaving 4x?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
oh well, um let's be careful a sec :)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
We can write our problem like this,\[\large \lim_{x \rightarrow 4}\frac{\left(\frac{4+x}{4x}\right)}{4+x} \qquad =\qquad \lim_{x \rightarrow 4} \left(\frac{4+x}{4x}\right)\cdot \frac{1}{4+x}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Maybe this will help you see what's going on better. So what happens when we cancel those out? :O
 one year ago

adam32885 Group TitleBest ResponseYou've already chosen the best response.0
it is 1/4x so the lim will be 1/16
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yay good job \c:/
 one year ago

adam32885 Group TitleBest ResponseYou've already chosen the best response.0
thank you!
 one year ago
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