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 2 years ago
How to integrate (62x)^2 . (indefinite integral). I'm trying U sub but Idk what I'm doing wrong
 2 years ago
How to integrate (62x)^2 . (indefinite integral). I'm trying U sub but Idk what I'm doing wrong

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TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1what did you use for u ?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1can you show your sork? what did you get for du? what did you get for dx?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.1U = 62x du = 2dx \[(1/2) \int\limits_{}^{} 2U^2dx\] @TuringTest

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1I'm not seeing where you get the 2 from... u=62x du=2dx > dx=du/2

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.1It's to get du right ? so I multiply by 1 pretty much 2/2

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1you have left your integral all mixed up with u integrated with respect to x; you can't do that. I think you are getting confused there. you need to sub in the values: u=62x du=2dx > dx=du/2 subbing in for u and dx gives\[\int u^2(\frac{du}2)=\frac12\int u^2du\]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.1We weren't taught how to solve for dx and plug back in but I like that way!

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1I sort of never saw them do it in class that way either, I never understood why :p

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.1@TuringTest What answer are you getting ? I get \[\frac{(62x)^{3}}{6} +c\] But my TI89 is giving me\[\frac{4(x3)^{3}}{3} +C\]

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1it is the same answer; they appear to have factored out a 2 in your TI89
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