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 one year ago
How to integrate (62x)^2 . (indefinite integral). I'm trying U sub but Idk what I'm doing wrong
 one year ago
How to integrate (62x)^2 . (indefinite integral). I'm trying U sub but Idk what I'm doing wrong

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TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1what did you use for u ?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1can you show your sork? what did you get for du? what did you get for dx?

3psilon
 one year ago
Best ResponseYou've already chosen the best response.1U = 62x du = 2dx \[(1/2) \int\limits_{}^{} 2U^2dx\] @TuringTest

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1I'm not seeing where you get the 2 from... u=62x du=2dx > dx=du/2

3psilon
 one year ago
Best ResponseYou've already chosen the best response.1It's to get du right ? so I multiply by 1 pretty much 2/2

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1you have left your integral all mixed up with u integrated with respect to x; you can't do that. I think you are getting confused there. you need to sub in the values: u=62x du=2dx > dx=du/2 subbing in for u and dx gives\[\int u^2(\frac{du}2)=\frac12\int u^2du\]

3psilon
 one year ago
Best ResponseYou've already chosen the best response.1Ohhh thank you turing!

3psilon
 one year ago
Best ResponseYou've already chosen the best response.1We weren't taught how to solve for dx and plug back in but I like that way!

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1I sort of never saw them do it in class that way either, I never understood why :p

3psilon
 one year ago
Best ResponseYou've already chosen the best response.1@TuringTest What answer are you getting ? I get \[\frac{(62x)^{3}}{6} +c\] But my TI89 is giving me\[\frac{4(x3)^{3}}{3} +C\]

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1it is the same answer; they appear to have factored out a 2 in your TI89
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