## mlddmlnog 2 years ago Help ! :'( I will post the problem below:

1. mlddmlnog

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2. mlddmlnog

@abb0t

3. abb0t

The bonds are N2 one N≡N bond (triple bond) H2 one H-H bond NH3 three N-H bonds Hence: ΔH = D(N≡N) + 3·D(H-H) - 2·3·D(N-H) 942kJ/mol + 3·432kJ/mol - 6·386kJ/mol = ______________

4. mlddmlnog

ahh thank you SO much!!!! @abb0t !

5. mlddmlnog

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6. mlddmlnog

@abb0t ?

7. mlddmlnog

8. mlddmlnog

9. abb0t

Remember that breaking a bond gives off heat and forming a bond consumes heat there4 lets look at the equation. I had to look up those values, you should be able to look them up in your book, i think they are lsted in the back of your book. Do the same thing I did with the last problem.

10. abb0t

I don't have all the values, but I have a few here in front of me: C=N is 891 C-H is 413 C≡N is 305 Please try it yourself first. I am not benefiting from giving you the answers, rather it is your duty to master this for your exam and or final.

11. mlddmlnog

@abb0t yes, i know. but what i actually need help is just to see how it is set up, and what the value of N triplebond C is. because it is not in the book.

12. abb0t

I already gave you some values there.