f(x)=2/x^2-2x-3 whats the range?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

f(x)=2/x^2-2x-3 whats the range?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

is the function f(x)=2/(x^2-2x-3) ?
yes
|dw:1358813023694:dw| solve for y

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

sorry i have mistake so look at this |dw:1358813276433:dw|
i am so sorry again look at this|dw:1358813417701:dw|
so 16Y^2 +8y>0 8y(2y+1) >0 then y>0 or y<-1/2
thats what I was going to write! sqrt16y^2+8y
how do I show it properly? most of my example show somethign like (-infinity, infinity) or (0, infinity) ect
|dw:1358813638796:dw|
thank you!

Not the answer you are looking for?

Search for more explanations.

Ask your own question