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petewe

  • 3 years ago

Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8

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  1. RyanL.
    • 3 years ago
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    First we want to get the slope which we will get from this equation 3x + 9y = 8 Can you tell me what the slope of this line is?

  2. petewe
    • 3 years ago
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    i just need the steps and the answer. i already learned the material back in september, just need some refreshing for the exam i have next week.

  3. RyanL.
    • 3 years ago
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    Oh ok First get the slope. Then find the derivative of x + ln x Set the derivative equal to the slope and solve for x. Plug the x into the original equation y = x + ln x to get y Now you have your slope m and point (x,y) Use point slope form (y-y1)=m(x-x1) where x1 and y1 is your point

  4. RyanL.
    • 3 years ago
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    You can leave it as it is or simplify it to y-intercept form.

  5. RyanL.
    • 3 years ago
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    Get it?

  6. petewe
    • 3 years ago
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    word, now i remember. thanks.

  7. RyanL.
    • 3 years ago
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    The slope is the negative reciprocal of the slope of this line 3x + 9y = 8 just fyi

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