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petewe
Group Title
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8
 one year ago
 one year ago
petewe Group Title
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8
 one year ago
 one year ago

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RyanL. Group TitleBest ResponseYou've already chosen the best response.1
First we want to get the slope which we will get from this equation 3x + 9y = 8 Can you tell me what the slope of this line is?
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
i just need the steps and the answer. i already learned the material back in september, just need some refreshing for the exam i have next week.
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.1
Oh ok First get the slope. Then find the derivative of x + ln x Set the derivative equal to the slope and solve for x. Plug the x into the original equation y = x + ln x to get y Now you have your slope m and point (x,y) Use point slope form (yy1)=m(xx1) where x1 and y1 is your point
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.1
You can leave it as it is or simplify it to yintercept form.
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
word, now i remember. thanks.
 one year ago

RyanL. Group TitleBest ResponseYou've already chosen the best response.1
The slope is the negative reciprocal of the slope of this line 3x + 9y = 8 just fyi
 one year ago
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