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 one year ago
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8
 one year ago
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8

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RyanL.
 one year ago
Best ResponseYou've already chosen the best response.1First we want to get the slope which we will get from this equation 3x + 9y = 8 Can you tell me what the slope of this line is?

petewe
 one year ago
Best ResponseYou've already chosen the best response.0i just need the steps and the answer. i already learned the material back in september, just need some refreshing for the exam i have next week.

RyanL.
 one year ago
Best ResponseYou've already chosen the best response.1Oh ok First get the slope. Then find the derivative of x + ln x Set the derivative equal to the slope and solve for x. Plug the x into the original equation y = x + ln x to get y Now you have your slope m and point (x,y) Use point slope form (yy1)=m(xx1) where x1 and y1 is your point

RyanL.
 one year ago
Best ResponseYou've already chosen the best response.1You can leave it as it is or simplify it to yintercept form.

petewe
 one year ago
Best ResponseYou've already chosen the best response.0word, now i remember. thanks.

RyanL.
 one year ago
Best ResponseYou've already chosen the best response.1The slope is the negative reciprocal of the slope of this line 3x + 9y = 8 just fyi
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