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anonymous
 3 years ago
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8
anonymous
 3 years ago
Find the equation of the tangent to the curve defined by y = x + ln x that is perpendicular to the line defined by 3x + 9y = 8

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0First we want to get the slope which we will get from this equation 3x + 9y = 8 Can you tell me what the slope of this line is?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i just need the steps and the answer. i already learned the material back in september, just need some refreshing for the exam i have next week.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh ok First get the slope. Then find the derivative of x + ln x Set the derivative equal to the slope and solve for x. Plug the x into the original equation y = x + ln x to get y Now you have your slope m and point (x,y) Use point slope form (yy1)=m(xx1) where x1 and y1 is your point

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You can leave it as it is or simplify it to yintercept form.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0word, now i remember. thanks.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The slope is the negative reciprocal of the slope of this line 3x + 9y = 8 just fyi
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