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AlbertoimusBest ResponseYou've already chosen the best response.0
3+6z=13+6z 6z=13+6z3 6z=10+6z z=(10+6z)/z
 one year ago

rejectz48Best ResponseYou've already chosen the best response.0
thank you @Albertoimus
 one year ago

AlbertoimusBest ResponseYou've already chosen the best response.0
oops sorry, the last one should be z=(10+6z)/6 . sorry, other than that you should be good.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
subtract 6z from both sides
 one year ago

rejectz48Best ResponseYou've already chosen the best response.0
no problem @Albertoimus thanks any way
 one year ago

rejectz48Best ResponseYou've already chosen the best response.0
i already did that @TuringTest
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
and what did you get? the answer provided by Albertoimus is wrong btw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
no that is incorrect 3 + 6z = 13 + 6z  6z  6z what are you left with?
 one year ago

AlbertoimusBest ResponseYou've already chosen the best response.0
why would you subtract 6z? s/he'll end up with 3=13, which is incorrect. s/he's trying to solve for z.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
@rejectz48 no, what albertoinus has is the correct result of subtracting 6z from both sides @Albertoimus this does tell you the answer; namely that there is no answer that is, no real solutions since 3=13 is never true.
 one year ago

rejectz48Best ResponseYou've already chosen the best response.0
so there is no solution @TuringTest
 one year ago

AlbertoimusBest ResponseYou've already chosen the best response.0
the solution should be z=(10+6z)/6. however, if you don't have a number to replace z, then there's no solution.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
if you follow through what you have and try to isolate z you get z=(10+6z)/6 z=5/3+z 0=5/3 again you see that by trying to solve for z you get a contradiction
 one year ago

rejectz48Best ResponseYou've already chosen the best response.0
ok.... @TuringTest @Albertoimus
 one year ago

AlbertoimusBest ResponseYou've already chosen the best response.0
all in all, no solution.
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
Possible solutions... x is unknown, a and b are constants x=a, one solution (a) x=x or a=a, infinite solutions a=b, no solutions
 one year ago
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