anonymous
  • anonymous
3 + 6z = 13 + 6z What does z equal?
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
3+6z=13+6z 6z=13+6z-3 6z=10+6z z=(10+6z)/z
anonymous
  • anonymous
thank you @Albertoimus
anonymous
  • anonymous
oops sorry, the last one should be z=(10+6z)/6 . sorry, other than that you should be good.

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TuringTest
  • TuringTest
subtract 6z from both sides
anonymous
  • anonymous
no problem @Albertoimus thanks any way
anonymous
  • anonymous
i already did that @TuringTest
TuringTest
  • TuringTest
and what did you get? the answer provided by Albertoimus is wrong btw
anonymous
  • anonymous
z=-10
TuringTest
  • TuringTest
no that is incorrect 3 + 6z = 13 + 6z - 6z - 6z what are you left with?
anonymous
  • anonymous
why would you subtract -6z? s/he'll end up with 3=13, which is incorrect. s/he's trying to solve for z.
anonymous
  • anonymous
3=13+1z @TuringTest
TuringTest
  • TuringTest
@rejectz48 no, what albertoinus has is the correct result of subtracting 6z from both sides @Albertoimus this does tell you the answer; namely that there is no answer that is, no real solutions since 3=13 is never true.
anonymous
  • anonymous
so there is no solution @TuringTest
anonymous
  • anonymous
the solution should be z=(10+6z)/6. however, if you don't have a number to replace z, then there's no solution.
TuringTest
  • TuringTest
if you follow through what you have and try to isolate z you get z=(10+6z)/6 z=5/3+z 0=5/3 again you see that by trying to solve for z you get a contradiction
anonymous
  • anonymous
ok.... @TuringTest @Albertoimus
anonymous
  • anonymous
all in all, no solution.
anonymous
  • anonymous
Possible solutions... x is unknown, a and b are constants x=a, one solution (a) x=x or a=a, infinite solutions a=b, no solutions

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