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bigworm

How do I find the maximum and minimum values of f(x)=x^3-5x^2+3x+12

  • one year ago
  • one year ago

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  1. tomo
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    set the second derivative equal to zero.

    • one year ago
  2. RyanL.
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    Find the derivative of f(x) and set it equal to zero. Solve for x.

    • one year ago
  3. RyanL.
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    I thought it was the first derivative?

    • one year ago
  4. tomo
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    yeah, you're right. the second derivative is to find if it is a min or a max. http://en.wikipedia.org/wiki/Second_derivative

    • one year ago
  5. RyanL.
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    Good point :D

    • one year ago
  6. bigworm
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    So how exactly do I find the first derivative?

    • one year ago
  7. tomo
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    have you had calculus?

    • one year ago
  8. RyanL.
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    First of you know what a derivative is right?

    • one year ago
  9. bigworm
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    No, im in algebra 2

    • one year ago
  10. RyanL.
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    =.=

    • one year ago
  11. bigworm
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    The way my teacher taught how to find the min and max is by using a calculator , but if there is an easier way by hand, I wanna know howw

    • one year ago
  12. amoodarya
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    • one year ago
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  13. amoodarya
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    this function is in odd degree so it has no max or min

    • one year ago
  14. bigworm
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    How do I find the min and max using a calculator then?

    • one year ago
  15. amoodarya
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    if the function was in even degree has a max or a min or both like that i draw|dw:1358815524977:dw|

    • one year ago
  16. tomo
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    instead of f(x) use y. also what kind of calculator do you have?

    • one year ago
  17. bigworm
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    ti-83

    • one year ago
  18. bigworm
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    so what should I do?

    • one year ago
  19. Action123
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    minimum: min{f(x) = x^3-5 x^2+3 x+12} = 3 at x = 3 max: max{f(x) = x^3-5 x^2+3 x+12} = 337/27 at x = 1/3

    • one year ago
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