anonymous
  • anonymous
How do I find the maximum and minimum values of f(x)=x^3-5x^2+3x+12
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
set the second derivative equal to zero.
anonymous
  • anonymous
Find the derivative of f(x) and set it equal to zero. Solve for x.
anonymous
  • anonymous
I thought it was the first derivative?

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anonymous
  • anonymous
yeah, you're right. the second derivative is to find if it is a min or a max. http://en.wikipedia.org/wiki/Second_derivative
anonymous
  • anonymous
Good point :D
anonymous
  • anonymous
So how exactly do I find the first derivative?
anonymous
  • anonymous
have you had calculus?
anonymous
  • anonymous
First of you know what a derivative is right?
anonymous
  • anonymous
No, im in algebra 2
anonymous
  • anonymous
=.=
anonymous
  • anonymous
The way my teacher taught how to find the min and max is by using a calculator , but if there is an easier way by hand, I wanna know howw
amoodarya
  • amoodarya
1 Attachment
amoodarya
  • amoodarya
this function is in odd degree so it has no max or min
anonymous
  • anonymous
How do I find the min and max using a calculator then?
amoodarya
  • amoodarya
if the function was in even degree has a max or a min or both like that i draw|dw:1358815524977:dw|
anonymous
  • anonymous
instead of f(x) use y. also what kind of calculator do you have?
anonymous
  • anonymous
ti-83
anonymous
  • anonymous
so what should I do?
anonymous
  • anonymous
minimum: min{f(x) = x^3-5 x^2+3 x+12} = 3 at x = 3 max: max{f(x) = x^3-5 x^2+3 x+12} = 337/27 at x = 1/3

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