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bigworm

  • 3 years ago

How do I find the maximum and minimum values of f(x)=x^3-5x^2+3x+12

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  1. tomo
    • 3 years ago
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    set the second derivative equal to zero.

  2. RyanL.
    • 3 years ago
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    Find the derivative of f(x) and set it equal to zero. Solve for x.

  3. RyanL.
    • 3 years ago
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    I thought it was the first derivative?

  4. tomo
    • 3 years ago
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    yeah, you're right. the second derivative is to find if it is a min or a max. http://en.wikipedia.org/wiki/Second_derivative

  5. RyanL.
    • 3 years ago
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    Good point :D

  6. bigworm
    • 3 years ago
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    So how exactly do I find the first derivative?

  7. tomo
    • 3 years ago
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    have you had calculus?

  8. RyanL.
    • 3 years ago
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    First of you know what a derivative is right?

  9. bigworm
    • 3 years ago
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    No, im in algebra 2

  10. RyanL.
    • 3 years ago
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    =.=

  11. bigworm
    • 3 years ago
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    The way my teacher taught how to find the min and max is by using a calculator , but if there is an easier way by hand, I wanna know howw

  12. amoodarya
    • 3 years ago
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  13. amoodarya
    • 3 years ago
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    this function is in odd degree so it has no max or min

  14. bigworm
    • 3 years ago
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    How do I find the min and max using a calculator then?

  15. amoodarya
    • 3 years ago
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    if the function was in even degree has a max or a min or both like that i draw|dw:1358815524977:dw|

  16. tomo
    • 3 years ago
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    instead of f(x) use y. also what kind of calculator do you have?

  17. bigworm
    • 3 years ago
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    ti-83

  18. bigworm
    • 3 years ago
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    so what should I do?

  19. Action123
    • 3 years ago
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    minimum: min{f(x) = x^3-5 x^2+3 x+12} = 3 at x = 3 max: max{f(x) = x^3-5 x^2+3 x+12} = 337/27 at x = 1/3

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