## bigworm 2 years ago How do I find the maximum and minimum values of f(x)=x^3-5x^2+3x+12

1. tomo

set the second derivative equal to zero.

2. RyanL.

Find the derivative of f(x) and set it equal to zero. Solve for x.

3. RyanL.

I thought it was the first derivative?

4. tomo

yeah, you're right. the second derivative is to find if it is a min or a max. http://en.wikipedia.org/wiki/Second_derivative

5. RyanL.

Good point :D

6. bigworm

So how exactly do I find the first derivative?

7. tomo

8. RyanL.

First of you know what a derivative is right?

9. bigworm

No, im in algebra 2

10. RyanL.

=.=

11. bigworm

The way my teacher taught how to find the min and max is by using a calculator , but if there is an easier way by hand, I wanna know howw

12. amoodarya

13. amoodarya

this function is in odd degree so it has no max or min

14. bigworm

How do I find the min and max using a calculator then?

15. amoodarya

if the function was in even degree has a max or a min or both like that i draw|dw:1358815524977:dw|

16. tomo

instead of f(x) use y. also what kind of calculator do you have?

17. bigworm

ti-83

18. bigworm

so what should I do?

19. Action123

minimum: min{f(x) = x^3-5 x^2+3 x+12} = 3 at x = 3 max: max{f(x) = x^3-5 x^2+3 x+12} = 337/27 at x = 1/3