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tomo
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1/cos(0)
rudra333
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\[\tan ^{-1}-\frac{ \sqrt{3} }{ 3}\]
rudra333
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@tomo is that the asnwer?
tomo
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?? that doesn't make sense. please reword
rudra333
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the one with tangent?
rudra333
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what is arccos0??
tomo
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cos(0) = 1.
rudra333
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@tomo
Inspired
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arccos(0)= 90 degrees or pi/2
tomo
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one second. it is a little different than i first thought it was.
rudra333
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k but plz try to expalin i have test on this toorrow
rudra333
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k what is the answer of the questio with tangent?
rudra333
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@Inspired
Inspired
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Well it's just the inverse of cos(0). Cos(0) =1. The inverse of that switches the values of the sine cosine functions. cos(90) gives you 1. but because remember, sin(0)=0 and sin(90)=1
Inspired
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cos(90) is 0*
Inspired
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and an easy way to remember is: sin is your y axis and cos is your x axis. the inverse of a function is basically switches the x and y. what was y=f(x) is now x=f(y)
rudra333
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k i know that but i have like 5 problems to work on i just want the right answers to it so i can practice
rudra333
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for the test tomorrow
rudra333
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socan u tell me the answer to the tangent one?plz
rudra333
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\[\arcsin-\frac{ \sqrt{3} }{ 2 }\]
rudra333
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and this one plz i have to go emergency plz answe those 2 for me plz
rudra333
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that will be really helpful
Inspired
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-pi/6 and -pi/3 (take a look at the unit circle for the second one)
fgoh
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how did u get -pi/6? i know in the unit cirlce but when i tried all of them tan is y/x then which onw will work?
fgoh
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@Inspired
Inspired
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Let's see. arctan (sqrt3/3) is the same thing as arctan (1/sqrt3) right? and using 30-60-90 triangle, you have this:
|dw:1358819026253:dw|
Inspired
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Anyway, since the value is negative, it will occur in the 2nd or 4th Quadrant. Since we want a single value, you usually use the 4th quadrant, and that gives you a negative value.
fgoh
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but is is y/x right why it doesn't work
fgoh
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if u do it with the values on unit square and i thought the domain is from (pi/2,-pi/2)?
fgoh
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|dw:1358819636475:dw|
fgoh
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OMG K GET IT THANKS THANKS ALOT @Inspired U ARE AWESOME AND HELPFUL OMG THANKS THANKS I JUST FEEL SO HAPPY WHEN I GET IT THANKS
Inspired
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:)
fgoh
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\[COS ^{-1}(\sin 11\pi/6)\]
fgoh
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@Inspired
fgoh
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@Inspired last one
fgoh
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and which one do u do first?
Inspired
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ok :0
sin(11pi/6) is the same thing as sin(12pi/6-pi/6) so you get sin(2pi-pi/6) -->
-sin(pi6)=-1/2
and so you have arccos(-1/2)
rudra333
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is that the answer arccos(-1/20)