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1/cos(0)

\[\tan ^{-1}-\frac{ \sqrt{3} }{ 3}\]

?? that doesn't make sense. please reword

the one with tangent?

what is arccos0??

cos(0) = 1.

arccos(0)= 90 degrees or pi/2

one second. it is a little different than i first thought it was.

k but plz try to expalin i have test on this toorrow

k what is the answer of the questio with tangent?

cos(90) is 0*

for the test tomorrow

socan u tell me the answer to the tangent one?plz

\[\arcsin-\frac{ \sqrt{3} }{ 2 }\]

and this one plz i have to go emergency plz answe those 2 for me plz

that will be really helpful

-pi/6 and -pi/3 (take a look at the unit circle for the second one)

but is is y/x right why it doesn't work

if u do it with the values on unit square and i thought the domain is from (pi/2,-pi/2)?

|dw:1358819636475:dw|

:)

\[COS ^{-1}(\sin 11\pi/6)\]

and which one do u do first?

is that the answer arccos(-1/20)