Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A compound has a pKa of 7.4. To 100mL of a 1.0M solution of this compound @ pH 8.0 is added 30mL of 1.0M HCl. What is the resulting pH?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

This is supposed to be review material for me, but I barely remember how to go about solving this stuff, lol! Would I need to do an ICE table? I feel like that isn't the case, because I don't know what one compound is...
Then I remembered about the Henderson-Hasselbach equation but that's not really helping, hahaha... Thinking maybe use the pH to kind the concentration and added that to the concentration of the HCl, but the HCl has such a high concentration that it's almost meaningless. If the pH is within 1 unit of the pKa then it's a good buffer, right?
pH = 7.4 simply means your substance is a base. Write it as \(B\), and write down the equation it undergoes with \(HCl\) Then use the new amounts in the Henderson equation.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

"Write it as B"? What's B?

Not the answer you are looking for?

Search for more explanations.

Ask your own question