A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
a math question
anonymous
 3 years ago
a math question

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\cos ^{1}(\sin \frac{ 11\pi }{ 6 })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 plz help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Play with the values for this one... Let \[x = \cos^{1}(\sin \frac{11\pi}{6})\]and if we get the cosine of both sides, we are left with...\[\cos x = \sin \frac{11\pi}{6}\]perhaps it's simpler from here on in?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answer is 2pi/3 ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You're right. Hang on... in general, \[\cos(\frac{\pi}{2}  \theta)=\sin(\theta)\] So \[\sin\frac{11\pi}{6}=\cos \left( \frac{\pi}{2}\frac{11\pi}{6} \right)\] \[=\cos \left( \frac{8\pi}{6} \right)\] It would appear \[x=\frac{4\pi}{3}+2k\pi\] where k is any integer. But since we're talking angles, adding 360 degrees, or 2pi, would give the same angle. Consider doing that here, because that negative angle ain't pretty XD \[x = \frac{4\pi}{3}+2\pi=\frac{2\pi}{3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k thanks but this other one is hard \[\tan(\sin ^{1}\frac{ 5 }{ 13 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's a bit complicated, but think of it this way... the SINE of the angle is 5/13, so what is its TANGENT?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here's what you do: sine of what angle will equal 5/13? Then you take that angle and take the tan of it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i how do i do that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer is 5/12 by the way

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358823550014:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so... tan of theta is ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how did u get 12? and one is negative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oops didn't catch the negative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if its negative then it means the angle is either in the third or fourth quadrant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0however my answer would still be correct if the angle was in the 3rd quadrant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Im sorry, i dont know how to work this out.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did the problems include restrictions?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but that's all the questions says

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0?? so is there or is there no restrictions like 180<theta<270 (for exmaple)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no that is all the question says do u know the answer plz i am confused i will just do others if u don't know this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright... shoot gimme another question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is k i am doing graphing
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.