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cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

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you need \(\sin(\theta)\) so compute these do you know how to find it?
the identities?

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Other answers:

sin 2 theta = 2 sin theta cos theta cos 2 theta = 2 cos ^2 theta - 1 tan 2 theta = sin 2 theta / cos 2 theta
do i plug in 4/5 where theta is?
If costheta=4/5 then sintheta= 3/5 \[\sin2\theta=2\sin\theta \cos\theta\]
there is a picture of an angle whose cosine is \(\frac{4}{5}\) you find the third side by pythagoras, or recalling the 3 - 4 - 5 right triangle this tells you \(\sin(\theta)=\frac{3}{5}\)
oh okay
so 2 sin theta = 2 sin 3/5 cos 4/5
no do not make that mistake, it is a common one do not use \(\theta=\frac{4}{5}\) use \(\cos(\theta)=\frac{4}{5}\) so \[\sin(2\theta)=2\times \frac{4}{5}\times \frac{3}{5}\]
no not the cosine and sine of those numbers, those numbers ARE the cosine and sine
use the numbers themselves, they are your sines and cosines
okay thank you!
your good now right?
im still confused a little ..

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