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1. Jemurray3

What do you need help with? I don't want to just do it and give it to you...

2. drfrankenstein

well, it is our first week of class and so far we have learn about black body radiation but I don't how it relate to first question , if it does at all

3. Jemurray3

It does, insofar as it requires a conceptual understand of how radiation works. You should consider that the frequency of a photon is proportional to the energy it carries. A photon of a very specific energy (and frequency) is required to raise the electron from energy level 0 to energy level 2. When it falls from 2 to 1, it releases a photon whose energy is equal to the difference in E2 and E1. The same is true for the transition from 1 to 0.

4. drfrankenstein

so more energy equal more frequency and energy absorbed should be largest , hence f_abs>f_ph

5. drfrankenstein

correct?

6. Jemurray3

yes, that's right.

7. Jemurray3

Though if we're being picky you should say "More energy, higher frequency"

8. drfrankenstein

also , in second question , I am thinking two ways 1) difference between E2 to E1 is smaller than E1 to E0 so F_fl is less than F_ph 2) E2 is at higher energy level than E1 , hence f_ph is less than f_fl

9. Jemurray3

(1) is correct. It doesn't matter what the energy levels are. The only thing that matters is the difference in energy between the two levels.

10. drfrankenstein

thank you very much for your help; I now have at least some idea going in second week of class

11. Jemurray3