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Solve the following equation, giving the exact solutions which lie in [0, 2π). (Enter your answers as a commaseparated list.)
sin(2x) = sin(x)
 one year ago
 one year ago
Solve the following equation, giving the exact solutions which lie in [0, 2π). (Enter your answers as a commaseparated list.) sin(2x) = sin(x)
 one year ago
 one year ago

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DeoxNABest ResponseYou've already chosen the best response.0
There's a pythagorean identity that says: sin(2x)=2*sin(x)*cos(x). so... 2cos(x)=1 cos(x)=1/2 And here's when your trig flashcards come in handy...
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
for some reason... i'm getting x = 0, pi/3/5pi/3 as the answers
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
No, you're right, I'm wrong. Doing it graphically I do get your answers. That's odd...let me think...
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
but when i plug them in the program says I'm wrong
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
mine. because there is a box that says x=
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
NO...you get \[x=0, \frac{ \pi }{ 3 }, \pi, \frac{ 5\pi }{ 6 }, 2\pi\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
@DeoxNA erased a solution.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
by dividing \[\sin\theta\], you erase values. that's the worst mistake you can do in these questions.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[\sin(2x)\sin(x)=0\] \[2\sin(x)\cos(x)\sin(x)=0\] \[\sin(x)(2\cos(x)1)=0\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[\sin(x)=0\] or \[\cos(x)=\frac{ 1 }{ 2 }\]
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
Hey Asteck can I ask you another question or DeoxNa
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
Yeah I was thinking about that, like when you get holes in the graph when you simplify rational functions...Well thank you @Azteck .
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
@dainel40 Sure thing...
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
Given the information below, find the exact values of the remaining circular functions of θ. sec(θ) = 10 with θ in Quadrant IV I got Sine= sqrt(99)/10 Cos= 1/10 But I can't get Tangent... I tried doing Sine/Cos but I get the wrong answer
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
To get tangent... shouldnt i do sine/cos?
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
I'm sorry, but I don't really get what you're doing. Are you trying to convert the secant to the other circular functions? Or do you replace the secant with each respective function?
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
im just trying to get Tangent ... I already know what sine and cos are
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
Given the information below, find the exact values of the remaining circular functions of θ. sec(θ) = 10 with θ in Quadrant IV I got Sine= sqrt(99)/10 Cos= 1/10 But I can't get Tangent... I tried doing Sine/Cos but I get the wrong answer
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
Like I already know Sine and Cosine,.. Idk how to get Tangent
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
Ok, sorry I didn't get what you were saying at first....Somehow I got it this time, so if: sec(θ)=10 in Quadrant IV θ=4.8122 tan(4.8122)=9.985. How did you get an exact theta?
 one year ago

dainel40Best ResponseYou've already chosen the best response.0
It's √99/10. sin^2 + cos^2 = 1 (1/10)^2 + sin^2 = 1 1/100 + sin^2 = 1 sin^2 = 99/100 sin = ± √ (99/100) = ± √99 / √100 = ± √99 / 10
 one year ago

DeoxNABest ResponseYou've already chosen the best response.0
Are you sure its not (√ 99/10)/(1/10)=√ 99 ? I know I'm not being much help, but its just that the answer makes perfect sense...
 one year ago
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