anonymous
  • anonymous
Find x. image of a triangle whose upper left corner is labeled 60 degrees and upper right corner has a box; the slanted side from upper left to lower right is labeled 16 and the vertical side is labeled x A. 8 B. 8 times the square root of 3 C. 16 times the square root of 3 D. 1 point 8 times the square root of 3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
SOHCAHTOA!!!
anonymous
  • anonymous
Sine=Opposite/Hypotenuse Cosine=Adjacent/Hypotenuse Tan= Opposite/Adjacent

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anonymous
  • anonymous
\[\sin(60)=\frac{x}{16}\]
anonymous
  • anonymous
Im goin wit d

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