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somebodys_heartbrake

  • 3 years ago

Find x. image of a triangle whose upper left corner is labeled 60 degrees and upper right corner has a box; the slanted side from upper left to lower right is labeled 16 and the vertical side is labeled x A. 8 B. 8 times the square root of 3 C. 16 times the square root of 3 D. 1 point 8 times the square root of 3

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  1. somebodys_heartbrake
    • 3 years ago
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  2. Azteck
    • 3 years ago
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    SOHCAHTOA!!!

  3. Azteck
    • 3 years ago
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    Sine=Opposite/Hypotenuse Cosine=Adjacent/Hypotenuse Tan= Opposite/Adjacent

  4. Azteck
    • 3 years ago
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    \[\sin(60)=\frac{x}{16}\]

  5. ninjaboy534
    • 3 years ago
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    Im goin wit d

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