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Gabbruce Group Title

Help Please! A sample of iron was heated to 125.0ºC, then placed into 375g of water at 19.8ºC. The temperature of the water rose to 29.7ºC. How many grams of iron where in the sample?

  • one year ago
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  1. Gabbruce Group Title
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    What would be the set up?

    • one year ago
  2. swissgirl Group Title
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    @abb0t :P

    • one year ago
  3. Gabbruce Group Title
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    That does not help.

    • one year ago
  4. swissgirl Group Title
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    I know what u mean :)

    • one year ago
  5. Gabbruce Group Title
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    Help please.

    • one year ago
  6. swissgirl Group Title
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    I remember doing this in High school but not sure what the method is. I am tooo lazy to bring down my notes

    • one year ago
  7. Gabbruce Group Title
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    You did this in High School? Ha I'm doing this in college but its okay thanks.

    • one year ago
  8. swissgirl Group Title
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    I did it in 12th grade

    • one year ago
  9. Gabbruce Group Title
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    I am doing this freshman year in college and having trouble with it.

    • one year ago
  10. Preetha Group Title
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    The fundamental concept is that heat lost = heat gained. Heat is lost by the iron rod and gained by the water. Heat lost by iron = m.s.(Ti-Tf). Heat gained by water is m.s. (Ti-Tf). Can you do this from here? s= specific heat, m = mass.

    • one year ago
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