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Gabbruce

  • one year ago

Help Please! A sample of iron was heated to 125.0ºC, then placed into 375g of water at 19.8ºC. The temperature of the water rose to 29.7ºC. How many grams of iron where in the sample?

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  1. Gabbruce
    • one year ago
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    What would be the set up?

  2. swissgirl
    • one year ago
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    @abb0t :P

  3. Gabbruce
    • one year ago
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    That does not help.

  4. swissgirl
    • one year ago
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    I know what u mean :)

  5. Gabbruce
    • one year ago
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    Help please.

  6. swissgirl
    • one year ago
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    I remember doing this in High school but not sure what the method is. I am tooo lazy to bring down my notes

  7. Gabbruce
    • one year ago
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    You did this in High School? Ha I'm doing this in college but its okay thanks.

  8. swissgirl
    • one year ago
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    I did it in 12th grade

  9. Gabbruce
    • one year ago
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    I am doing this freshman year in college and having trouble with it.

  10. Preetha
    • one year ago
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    The fundamental concept is that heat lost = heat gained. Heat is lost by the iron rod and gained by the water. Heat lost by iron = m.s.(Ti-Tf). Heat gained by water is m.s. (Ti-Tf). Can you do this from here? s= specific heat, m = mass.

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