A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Bifurcation diagrams. No idea what i'm doing...
The differential equation depends on a parameter \(a\in\mathbb{R}\). Find the equilibrium points and determine whether they are source, sink or neither and sketch the bifurcation diagram. \[x'(t)=x^32ax^2+4x\] where \(a\geq 0\)
 one year ago
Bifurcation diagrams. No idea what i'm doing... The differential equation depends on a parameter \(a\in\mathbb{R}\). Find the equilibrium points and determine whether they are source, sink or neither and sketch the bifurcation diagram. \[x'(t)=x^32ax^2+4x\] where \(a\geq 0\)

This Question is Closed

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0If I remember correctly, to find the equilibrium points, find the zero's. So factor out an x... \[x(x^22ax+4)=0\]

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0plug in the equilibrium points for f'. and If f is less than the equilibrium points then it's a source, and sinks if it's greater than equilibrium point.

richyw
 one year ago
Best ResponseYou've already chosen the best response.0ok what I am struggling with is how to split it up. like for some values of a there are a different amount of equlibrium points. are there any resources that just explain what is going on? i'm at my wits end with Hirsch, Differential equations. There isn't even a solution manual

swissgirl
 one year ago
Best ResponseYou've already chosen the best response.0I found something that may be helpful

swissgirl
 one year ago
Best ResponseYou've already chosen the best response.0Go to page 53 Example 31
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.