x^2*y' + 3xy = 1 (Linear DE)

x^2*y' + 3xy = 1 (Linear DE)

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

I divide by x^2 to get
y' + (3/x)y=1/x^2
My integration factor though gives me |x|^3

I dunno what to do with this absolute value :S

is it \[x ^{2}y \prime +3xy=1\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.