x^2*y' + 3xy = 1 (Linear DE)

x^2*y' + 3xy = 1 (Linear DE)

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I divide by x^2 to get
y' + (3/x)y=1/x^2
My integration factor though gives me |x|^3

I dunno what to do with this absolute value :S

is it \[x ^{2}y \prime +3xy=1\]

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